Answer:5
Step-by-step explanation:
<h3><u>(8 + 2)</u> <u>sum of values </u> = <u>10</u> = 5</h3><h3> 2 number of values 2</h3><h3 />
There is equal spacing between the mean and the extremes
8 - 5 = 3
5 - 2 = 3
Answer:
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
d. z= 1.3322
Step-by-step explanation:
We formulate our hypothesis as
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
According to the given conditions
p`= 31/225= 0.1378
np`= 225 > 5
n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5
p = 0.4 x= 31 and n 225
c. Using the test statistic
z= p`- p / √pq/n
d. Putting the values
z= 0.1378- 0.11/ √0.11*0.89/225
z= 0.1378- 0.11/ √0.0979/225
z= 0.1378- 0.11/ 0.02085
z= 1.3322
at 5% significance level the z- value is ± 1.645 for one tailed test
The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept Ha : p >0.11 and conclude that the data indicates that the 11% of the world's population is left-handed.
The rejection region is attached.
The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.
which appears to be 0.95 and subtracting from 1 gives 0.04998
Answer:
A total of 720 elk are likely to be infected
Step-by-step explanation:
we shall be using the proportion by survey to estimate the number of infections
From the survey 8 out of 50 are infected. Thus the likelihood of infection is 8/50
We have 4,500 elk to consider. The number of elk likely to be infected will be 8/50 * 4500 = 720
The answer to the problem is 24