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mr_godi [17]
3 years ago
13

I need help don’t understand

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0
If f(x)=x+1 and then x became 2, you would have the function f(x)=3. So basically for that function you would be going up three over 1. That function is already g(x)=4x. If X became 2, you would have g(x)=8x. The rate of up 8 and then over one. Because of that, g(x) would be higher
Mama L [17]3 years ago
8 0

okay first off: we both use the same virtual school and i just thought that was cool lol

the equation for g(x) is g(x)=4x-5 so when you substitute in x it becomes

g(x)= 4(2) -5 or g(x)= 8-5 which equals g(x)=3

when you substitute in x, f(x) becomes

f(x)= 2 + 1 which equals f(x)=3

therefore when x=2, both functions are equal :)

hope this helps!!

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∠K and ∠L are complementary angles. If m∠K = 3x + 3 and m∠L = 10x – 4, find the measures of both angles.
Oduvanchick [21]

Answer:

∠K =24

∠L =66

Step-by-step explanation:

first you need to find X in order to solve.

since they are Complementary they add together to equal 90 degrees

so we can set them equal to 90

13x-1=90

13x=91

x=7

now we can plug them in!

---

∠K = 3(7)+3 = 24

∠L =10(7)-4=66

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At the fair, the ratio of males to females was 4:5. If there are 180 people at the fair, how mamy males are there?​
Setler79 [48]

Answer:

80 males

Step-by-step explanation:

180 / 9 = 20

20 x 4 = 80

3 0
2 years ago
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Givens

Let the number of students in the class be x

Let the number of pieces of gum she gave out be 3x

Equation

3x + 8 = 168 This will not work out evenly. Let's try x - 1. The reason for that is because she may not give out anything to herself.

3(x - 1) + 8 = 168      This doesn't work either.

Well we have to choose. It's a rounding problem.

3x + 8 = 168     Subtract 8 from both sides.

3x = 168 - 8      Combine

3x = 160           Divide by 3 on both sides.

x = 160 / 3

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Since that can't be, we could say there were 53 students.

3x

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