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poizon [28]
3 years ago
9

What is the runner’s average rate of change between the hours: 0.5 and 2? mph 1.5 and 2.5? mph Average Rate of Change

Mathematics
2 answers:
lana [24]3 years ago
4 0

Answer:

0.5 and 2?  

4

mph  

1.5 and 2.5?  

5

mph

Base on these results, the runner ran at a  rate between 0.5 and 2 hours than between 1.5 and 2.5 hours.

slower

Step-by-step explanation:

alina1380 [7]3 years ago
4 0

Answer:

4 and 5

Step-by-step explanation:

I just took it. Edg 2020. Hope this helps :)

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A closed box has a square base with side length feet and height feet given that the volume of the box is 34 ft.³ express the sur
Deffense [45]

Answer:

\dfrac{2s^3+136}{s}

Step-by-step explanation:

Let the side length of the square base =s feet

Let the height of the box = h

Given that the volume of the box = 34$ ft^3

Volume of the box =s^2h

Then:

s^2h=34$ ft^3\\$Divide both sides by s^2\\h=\dfrac{34}{s^2}

Surface Area of a Rectangular Prism =2(lb+bh+lh)

Since we have a square base, l=b=s feet

Therefore:

Surface Area of our closed box= 2(s^2+sh+sh)

S$urface Area= 2s^2+4sh\\Recall: h=\dfrac{34}{s^2}\\$Surface Area= 2s^2+4s\left(\dfrac{34}{s^2}\right)\\=2s^2+\dfrac{136}{s}\\$Surface Area in terms of length only=\dfrac{2s^3+136}{s}

7 0
3 years ago
Can someome please help me solve this my teacher hasn't done a good with teaching us this.
scoundrel [369]

Answer:

  30500 = 3.05·10^4

Step-by-step explanation:

Your calculator can do this for you. You may need to set the display to scientific notation, if that's the form of the answer you want.

__

This can be computed by converting both numbers to standard form:

  (5·10^2) +(3·10^4)

  = 500 +30000 = 30500 = 3.05·10^4

__

Addition of numbers in scientific notation in general requires that they have the same power of 10. It may be convenient to convert both numbers to the highest power of 10.

  5·10^2 + 3·10^4

  = 0.05·10^4 +3·10^4 . . . . now both have multipliers of 10^4

  = (0.05 +3)·10^4

  = 3.05·10^4

5 0
3 years ago
(27 thousands 3 hundreds 5 ones) x 10
anyanavicka [17]

Answer:

Two hundred seventy three thousand and fifty .

Step-by-step explanation:

Given : (27 thousands 3 hundreds 5 ones) x 10

Solution:

27 thousands 3 hundreds 5 ones = 27,305

So, 27,305 \times 10

273,050

Periods are counted from last .

The 1st period consists of ones, tens and hundred.

The 2nd period consists of  thousand, 10 thousand and 100 thousands.

The 3rd period consists of  million, 10 million and 100 million.

So, 273,050 is Two hundred seventy three thousand and fifty

Hence (27 thousands 3 hundreds 5 ones) x 10 is Two hundred seventy three thousand and fifty .

4 0
3 years ago
Read 2 more answers
Factor completely 9r^3-72r^2
PtichkaEL [24]

Answer:

9r²(r - 8)

Step-by-step explanation:

Step 1: Write expression

9r³ - 72r²

Step 2: Factor out 9

9(r³ - 8r²)

Step 3: Factor out r²

9r²(r - 8)

6 0
3 years ago
The sum of two consecutive even integers is 2 find two integers
pochemuha

the two consecutive even integers are:

x

x+2

x+x+2=2

2x+2=2

2x=0

x=0

x+2=2

7 0
3 years ago
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