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fgiga [73]
3 years ago
9

Suppose each of 12 players rolls a pair of dice 3 times. Find the probability that at least 4 of the players will roll doubles a

t least once. (Answer correct to four decimal places.)
Mathematics
1 answer:
polet [3.4K]3 years ago
7 0

Answer:

Our answer is 0.8172

Step-by-step explanation:

P(doubles on a single roll of pair of dice) =(6/36) =1/6

therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)

=1-(1-1/6)3 =91/216

for 12 players this follows binomial distribution with parameter n=12 and p=91/216

probability that at least 4 of the players will get “doubles” at least once =P(X>=4)

=1-(P(X<=3)

=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)

=1-0.1828

=0.8172

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In a race between 18 people, how many ways can the top 5 finishers be arranged?
snow_lady [41]

Answer:

Step-by-step explanation:

This is permutation, since order matters.  The formula for us is

₁₈P₅ = \frac{18!}{(18-5)!} which simplifies to

₁₈P₅ = \frac{18*17*16*15*14*13!}{13!}

The factorial of 13 cancels out on the top and bottom leaving you with

₁₈P₅ = 18 × 17 × 16 × 15 × 14

which comes to 1,028,160 ways

Another way to look at it is:  the first 5 people of 18 finish and the others you don't care about.  Once the first place person is first, there are only 4 of the 18 left to finish in second place.  Then there are only 3 left to finish in third place, etc.  So if we use that reasoning, we don't even need to use the formula, we can just say

18 * 17 * 16 * 15 * 14 and those are the first 5 people of 18 to finish.

8 0
3 years ago
Solve for x: 2 over 3 equals the quantity x minus 1 end quantity over 5
sweet-ann [11.9K]

Answer:

13 over 3

Step-by-step explanation:

Hi Jakeyriabryant! I hope you’re fine!

I hope I have understood the problem well.

If so, what the exercise raises is the following equality:

(x-1) / 5 = 2/3

From this equation you must clear the "x".

First, we pass the 5 that is dividing on the side of the x, to the other side and passes multiplying

(X – 1) / 5 = 2/3  

(X – 1) = (2/3)*5

X – 1 = 10/3

Then we pass the one that is subtracting from the side of the x, to the other side and passes adding

X  = 10/3 + 1

Remember that to add or subtract fractions they must have the same denominator or a common denominator (in this case we can write 1 as fraction 3/3). Then,

X = 10/3 + 3/3

X = 13/3

I hope I've been helpful!

Regards!

7 0
3 years ago
A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, don’
cupoosta [38]

Answer:

The height of rectangle is 5 inches

Step-by-step explanation:

<u><em>The correct question is</em></u>

A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, Find the height

Let

x -----> the width of the rectangle in inches

y ----> the height of the rectangle in inches

d ---> diagonal measurement of the rectangle in inches

we know that

Applying the Pythagorean Theorem

d^2=x^{2}+y^{2}

we have

d=13\ in

so

13^2=x^{2}+y^{2}

169=x^{2}+y^{2} ----> equation A

x=y+7 ---> equation B

substitute equation B in equation A

169=(y+7)^{2}+y^{2}

solve for y

169=y^2+14y+49+y^{2}

2y^2+14y+49-169=0

2y^2+14y-120=0

solve the quadratic equation by graphing

using a graphing tool

The solution is y=5

see the attached figure

therefore

The height of rectangle is 5 inches

5 0
2 years ago
The question is below​
Cloud [144]

Answer:

See below.

Step-by-step explanation:

a.

The first figure has 1 square. The second figure has a column of 2 squares added to the left. The third figure has a column of 3 squares added to the left. Each new figure has a column of squares added to the left containing the same number of squares as the number of the figure.

b.

Figure 10 has 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 squares.

c.

The formula for adding n positive integers starting at 1 is:

1 + 2 + 3 + ... + n = n(n + 1)/2

For figure 55, n = 55.

n(n + 1)/2 = 55(56)/2 = 1540

d.

Let's use the formula set equal to 190 and solve for n. If n is an integer, then we can.

n(n + 1)/2 = 190

n(n + 1) = 380

We know that 380 = 19 * 20, so n = 19.

Answer: yes

e.

Use the formula above,

S = n(n + 1)/2, where S is the sum.

f.

n(n + 1) = 1478

38 * 39 = 1482

37 * 38 = 1406

3 0
3 years ago
Write an expression that equals 24. Include an exponent.
kipiarov [429]
8x8x8 or 8 with the power of 3
6 0
2 years ago
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