n = m / M
Where, n is moles of the compound (mol), m is the mass of the compound (g) and M is the molar mass of the compound (g/mol)
Here, the given ethanol mass = 50.0 kg = 50.0 x 10³ g
Molar mass of the ethanol = (12 x 2 + 1x 6 + 1 x 16) g/mol
= 46 g/mol
Hence, moles in 50.0kg of ethanol = 50.0 x 10³ g / 46 g/mol
= 1086.96 mol
Answer:
103.98 kpa
Explanation:
Pv= nRT
Where
P= pressure of the system=
n= number of moles= 3 moles
T= temperature= 250 K
Volume of the container= 60 liters
R= 0.0821L.atm/K.mol
Substitute the values
Pv= nRT
P= nRT/ V
= (3×0.0821×250)/60
= 1.026 Atm
1atm= 101325 Pascal
1.026 atm= X
= 103984 pasca
Convert to kilopascal
= 103984 pasca /1000
= 103.98 kpascal
Uh, not sure if you're asking or not, but during beta decay TI-207 emits a beta particle.