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ozzi
3 years ago
11

Ethanol (c2h6o) is a common intoxicant and fuel produced from the fermentation of various grains. how many moles of ethanol are

represented by 50.0 kg of ethanol?
Chemistry
1 answer:
Lynna [10]3 years ago
3 0
n = m / M

Where, n is moles of the compound (mol), m is the mass of the compound (g) and M is the molar mass of the compound (g/mol)

Here, the given ethanol mass = 50.0 kg = 50.0 x 10³ g

Molar mass of the ethanol = (12 x 2 + 1x 6 + 1 x 16) g/mol
                                          = 46 g/mol

Hence, moles in 50.0kg of ethanol = 50.0 x 10³ g / 46 g/mol
                                                        = 1086.96 mol
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djverab [1.8K]

1.04 ⨯ 10^{-4} M

<h3>Explanation</h3>

<em>A</em> = <em>ε</em> \cdot l \cdot c by the Beer-Lambert law, where

  • <em>A</em> the absorbance,
  • l the path length,
  • <em>ε</em> the molar absorptivity of the solute, and
  • c concentration of the solution.

<em>A</em> and <em>ε </em>are the same for both solutions. Therefore, l \cdot c is constant; l is inversely proportional to c. The 100 mL sample would have a concentration 1/4.78 times that of the 45.0 mL reference.

The 13.0 mL standard solution has a concentration of 5.17 ⨯ 10^{-4} M. Diluting it to 45.0 mL results in a concentration of 5.17 \times 10^{-4} \times \frac{13.0}{45.0} = 1.494 M.

c is inversely related to l for the two solutions. As a result, c₂ = c_1 \cdot \frac{l_1}{l_2} = 1.494 \times 10^{-4} \times \frac{1}{4.78} = 3.126 M.

The 30.0 mL sample has to be diluted by 30.0 / 100.0 times to produce the 100.0 mL solution being tested. The 100.0 mL solution has a concentration of 3.126 M. Therefore, the 30.0 mL solution has a concentration of 3.126 \times \frac{100.0}{30.0} = 1.04 ⨯ 10^{-4} M.

6 0
3 years ago
Which element can join with other elements to form covalent bonds? beryllium (Be) carbon (C) cesium (Cs) iron (Fe)
Rainbow [258]

Answer:

Carbon (C)

Explanation:

Carbon is the only nonmetal there and covalent bonds happen between two nonmetal atoms

4 0
3 years ago
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What does it mean for the energy levels in an atom to be quantized? Describe how this affects where electrons can be found
marta [7]
When we describe the energy of a particle as quantized, we mean that only certain values of energy are allowed. ... In this case, whenever we measure the particle's energy, we will find one of those values. If the particle is measured to have 4 Joules of energy, we also know how much energy the particle can gain or lose. Quantized energy means that the electrons can possess only certain discrete energy values; values between those quantized values are not permitted
3 0
3 years ago
Convert 6.93 x 1024 atoms of carbon to moles of carbon.
Aleksandr [31]

Answer: 11.5 moles of carbon

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of carbon = 6.02 x 10^23 atoms

Z moles = 6.93 x 10^24 atoms

To get the value of Z, cross multiply:

(6.93 x 10^24 atoms x 1mole) = (6.02 x 10^23 atoms x Z moles)

6.93 x 10^24 = (6.02 x 10^23 x Z)

Z = (6.93 x 10^24) ➗ (6.02 x 10^23)

Z = 1.15 x 10

Z = 11.5 moles

Thus, there are 11.5 moles of carbon.

7 0
3 years ago
If we use 18 moles of H2 how many moles of H2O do we make? Use this chemical equation: 6H2 + O2 → 3H2O
Ilya [14]
<h3>Answer:</h3>

9 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>  

<u>Pre-Algebra</u>  

Order of Operations: BPEMDAS  

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>  

<u>Atomic Structure</u>  

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>  

  • Using Dimensional Analysis
  • Analyzing reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 6H₂ + O₂ → 3H₂O

[Given] 18 mol H₂

[Solve] mol H₂O

<u>Step 2: Identify Conversions</u>

[RxN] 6 mol H₂ → 3 mol H₂O

<u>Step 3: Stoich</u>

  1. [DA] Set up conversion:                                                                               \displaystyle 18 \ mol \ H_2(\frac{3 \ mol \ H_2O}{6 \ mol \ H_2})
  2. [DA] Simplify:                                                                                                 \displaystyle 18 \ mol \ H_2(\frac{1 \ mol \ H_2O}{2 \ mol \ H_2})
  3. [DA] Divide [Cancel out units]:                                                                     \displaystyle 9 \ mol \ H_2O
3 0
3 years ago
Read 2 more answers
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