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AlladinOne [14]
3 years ago
10

HELP! URGENT Which of the following best states the relationship between erosion and deposition?

Chemistry
1 answer:
MariettaO [177]3 years ago
7 0
The answer is A: When the energy transporting sediments diminishes, the sediments settle in a low-lying area; therefore, deposition always follows erosion
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Which list only includes terms that describe oxygen gas, Oz? (1 point)
Vilka [71]
Alright this to me seems to be the answer C if it’s not then that’s cuz I’m guessing
6 0
3 years ago
Watch the animation and identify the correct conditions for forming a hydrogen bond.
torisob [31]

Answer:

options B,C and E are correct conditions for forming hydrogen bonds.

Explanation:

In order for particles to stick together or shows certain characteristics, there must be a bond of attractions that is making them to be able to stay together. Some of these attractions are strong while some are weak. The kind of attraction that is being considered in this question  is the hydrogen  bonding which is considered as part of the weak forces of attractions.

In order for hydrogen bonds to occur, there must be hydrogen atoms [option B is correct] and a much more electronegative elements such as oxygen, Fluorine and Nitrogen. Hence, option C is correct.

Since the Fluorine or oxygen or nitrogen have much more electronegative properties than hydrogen, it causes a partial negative charge on  Fluorine or oxygen or nitrogen and a partial positive charge on the Hydrogen. Thus, option E is correct.

8 0
3 years ago
water at 400 kPa and 60°C while the other part is evacuated. The partition is now removed, and the water expands to fill the ent
kaheart [24]

Answer:

0.4912 kJ/K

Explanation:

Using steam table, the properties of water at stage 1 can be determined:

P_{1} = 400 kPa

T_{1} = 60°C

Therefore, from steam table:

specific volume v_{1}  = 0.001017 m^{3}/kg

entropy  s_{1}  = 0.8313 kJ/kg*K

Calculating the specific volume of water after the partition is removed, since the mass is constant and volume of water is doubled:

v_{2} = 2*0.001017 = 0.002034 m^{3}/kg

Final pressure of water in the tank = P_2} = 40 kPa

dryness factor after removing the partition

x = \frac{0.002034 - 0.001026}{3.993 - 0.001026} = 2.524*10^{-4} kg/vapor

Therefore:

s_{2} = s_{f2} + x*s_{fg2}  = 1.0261 + (2.524*10^{-4}*6.643) = 1.02778 kJ/kg*K

Thus, the entropy change is:

Δs = m*(s_{2}-s_{1}) = 2.5*(1.02778 - 0.8313) = 0.4912 kJ/K

Therefore, the entropy change of water is 0.4912 kJ/K

6 0
4 years ago
If 15 drops of ethanol from a medical dropper weight 0.60g, how many drops does it takes from a dropper to dispense 1.0ml of eth
Hoochie [10]

Answer : The number of drops it takes from a dropper to dispense 1.0 ml of ethanol is, 20 drops

Solution : Given,

Density of ethanol = 0.80 g/ml

Mass of ethanol = 0.60 g

First we have to calculate the volume of ethanol.

Formula used : Density=\frac{Mass}{Volume}

0.80g/ml=\frac{0.60g}{Volume}

Volume=\frac{0.60g}{0.80g/ml}=0.75ml

The volume of ethanol is, 0.75 ml

Now we have to calculate the number of drops it takes from a dropper to dispense 1 ml of ethanol.

As, the number of drops in 0.75 ml of ethanol = 15

So, the number of drops in 1.0 ml of ethanol = \frac{15}{0.75}\times 1.0=20

Therefore, the number of drops it takes from a dropper to dispense 1.0 ml of ethanol is, 20 drops

8 0
3 years ago
recieve 1.25 milligrams of conjugated estrogen per day. you have conjugated estrogens in 0.625 milligram tablets. how many table
Effectus [21]
2 tablets to be given daily.
4 0
3 years ago
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