-4x + y = 4 2x + 2y =13

Mathematics

2 answers:

schepotkina [342]3 years ago

4 0

Answer: What exactly are you asking??

Step-by-step explanation:

alukav5142 [94]3 years ago

4 0

Problem 1 Answer: x = -1 + 0.25y

Show Work:

1) Solving

-4x + y = 4

2) Solving for variable 'x'.

3) Move all terms containing x to the left, all other terms to the right.

4) Add '-1y' to each side of the equation.

-4x + y + -1y = 4 + -1y

5) Combine like terms: y + -1y = 0

-4x + 0 = 4 + -1y

-4x = 4 + -1y

6) Divide each side by '-4'.

x = -1 + 0.25y

7) Simplifying

x = -1 + 0.25y

Problem 2 Answer: x = 6.5 + -1y

Show Work:

1) Solving

2x + 2y = 13

2) Solving for variable 'x'.

3) Move all terms containing x to the left, all other terms to the right.

4) Add '-2y' to each side of the equation.

2x + 2y + -2y = 13 + -2y

5) Combine like terms: 2y + -2y = 0

2x + 0 = 13 + -2y

2x = 13 + -2y

6) Divide each side by '2'.

x = 6.5 + -1y

7) Simplifying

x = 6.5 + -1y

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b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.

Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ $2x$