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3 years ago

a right cylinder with radius 4 cm and height 3 cm 314 cu cm a cone with radius 5 cm and height 12 cm. what is the volume

1 answer:

3 0

The cylinder volume is 150.79644737231 centimeter^3
or 150.8

the cone's volume is 314.15926535898 centimeter^3
or 314.2

the cylinder equation to find it is π×42×3
the cone equation to find it is 1/3×π×52×12

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A square steel bar has a length of 5.1 ft and a 2.7 in by 2.7 in cross section and is subjected to axial tension. The final leng

Andrej [43]

Answer:

The Poisson's ratio for the material is 0.0134.

Step-by-step explanation:

The Poisson's ratio ( $\nu$ ), no unit, is the ratio of transversal strain ( $\epsilon_{t}$ ), in inches, to axial strain ( $\epsilon_{a}$ ), in inches:

$\nu = -\frac{\epsilon_{t}}{\epsilon_{a}}$ (1)

$\epsilon_{a} = l_{a,f}-l_{a,o}$ (2)

$\epsilon_{t} = l_{t,f}-l_{t,o}$ (3)

Where:

$l_{a,o}$ - Initial axial length, in inches.

$l_{a,f}$ - Final axial length, in inches.

$l_{t,o}$ - Initial transversal length, in inches.

$l_{t,f}$ - Final transversal length, in inches.

If we know that $l_{a,o} = 61.2\,in$ , $l_{a,f} = 61.235\,in$ , $l_{t,o} = 2.7\,in$ and $l_{t,f} = 2.69953\,in$ , then the Poisson's ratio is:

$\epsilon_{a} = 61.235\,in - 61.2\,in$

$\epsilon_{a} = 0.035\,in$

$\epsilon_{t} = 2.69953\,in - 2.7\,in$

$\epsilon_{t} = -4.7\times 10^{-4}\,in$

$\nu = - \frac{(-4.7\times 10^{-4}\,in)}{0.035\,in}$

$\nu = 0.0134$

The Poisson's ratio for the material is 0.0134.

7 0

3 years ago

How would I find the measurement of arc CD?

Ierofanga [76]

Angle A = (arc CD - arc BC) / 2
56 degrees = (arc CD -95) / 2
112 degrees = (arc CD -95)
arc CD = 207

4 0

4 years ago

I’ll give extra points!!

Svetach [21]

Answer:
10

Explanation:
The two shortest sides = the longest side
So I’m this case, the two shortest sides are 7 and 3, which are shown.
Then add:
7 + 3 = 10

6 0

3 years ago

If a baseball player has 5 hits in 20 at bats, what is the probability in the decimal to the thousandths place that he will get

k0ka [10]

Answer:

$Probability = 0.250$