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Neporo4naja [7]
3 years ago
6

Please Help! If (5x-2)^2=ax^2-bx+c, what is the value of a+c^2?

Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer:

The solved problem is in the photo. Hope it helps.

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There are 3.76 x 10 to the power of 22 atoms in 1 gram of oxygen. How many atoms are there in 600 grams of oxygen? Write your an
tatiyna

Answer:

<u>2.256 x 10 to the power of 25</u>

Step-by-step explanation:

There are 3.76 x 10 to the power of 22 atoms in 1 gram of oxygen

So, there are x atoms in 600 grams of oxygen

Using the ratio and proportional

So, the number of atoms = 600 * 3.76 x 10 to the power of 22 =

                                          = 6*10^2 * 3.76 * 10^{22}\\=6*3.76 * 10^2*10^{22}\\=22.56 * 10^{24}\\=2.256 * 10 * 10^{24}\\=2.256 * 10^{25}

So, the answer in scientific notation as A.BCD x 10 to the power of E

Will be <u>2.256 x 10 to the power of 25</u>

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Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*
dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\

5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\

\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3

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