Answer:
it will be 5.5 hours have a nice day
Equation of a parabola is given by
y = ax^2 + bx + c
From the given points
-16 = a(-2)^2 + b(-2) + c = 4a - 2b + c . . . (1)
4 = a(0)^2 + b(0) + c = c . . . (2)
-28 = a(4)^2 + b(4) + c = 16a + 4b + c . . . (3)
Putting (2) into (1) and (2) gives:
4a - 2b + 4 = -16
4a - 2b = -20 . . . (4)
16a + 4b + 4 = -28
16a + 4b = -32 . . . (5)
(4) x 4 => 16a - 8b = -80 . . . (6)
(5) - (6) => 12b = 48
b = 48/12 = 4
From (4), 4a - 2(4) = -20
4a = -20 + 8 = -12
a = -12/4 = -3
Therefore, the required polynomial is
y = -3x^2 + 4x + 4
Answer:
Attached
Step-by-step explanation:
The equation given is ;
y=√-x-3----------------------square left side to eliminate the root
y²= -x-3
graph y²= -x-3 on a graph tool
Answer:
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