I think it might be f^-1 (x) = x/2 - 3/2
I hope this helps!
Answer:
P(a junior or a senior)=1
Step-by-step explanation:
The formula of the probability is given by:

Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.
In this case, N is the total number of the students of statistics class.
N=18+10=28
The probability of the union of two mutually exclusive events is given by:

Therefore:
P(a junior or a senior) =P(a junior)+P(a senior)
Because a student is a junior or a senior, not both.
n(a junior)=18
n(a senior)=10
P(a junior)=18/28
P(a senior) = 10/28
P(a junior or a senior) = 18/28 + 10/28
Solving the sum of the fractions:
P(a junior or a senior) = 28/28 = 1
Answer:
a). 6:51
b). 6:30 am
c). 34 minutes
Step-by-step explanation:
a). Train leaves Westchester at 6:30.
From the arrival - departure table in column (2),
Arrival time of the train at middlewich = 6:51
b). Kate has to reach Southam before 9:00 am
Therefore, time of the latest train that she can catch to get to work on time is 6:30 am
By this train she can reach at 07:19 at Southam.
c). Duration of journey from Westchester to Eastwick = 06:34 - 06:00
= 00:34
≈ 34 minutes
Each waffle weighs 5.97 ounces hope this helps!
Answer:
P'Q' is equal in length to PQ.
Step-by-step explanation:
Before rotation
P(-5, 3)
Q(-1, 3)
we get the length
L = √((-1-(-5))²+(3-3)²) = √((-4)²+(0)²) = 4
After rotation
P'(3, 5)
Q'(3, 1)
we get the length
L' = √((3-3)²+(1-5)²) = √((0)²+(-4)²) = 4
we can say that L = L' = 4
P'Q' is equal in length to PQ.