For this case we have that the following function complies with the given conditions:
To prove it, let's find the roots of the polynomial:
By doing common factor 3 we have:
Factoring the second degree polynomial we have:
Then, the solutions are:
Solution 1:
Solution 2:
Answer:
A second degree polynomial function f (x) that has a lead coefficient of 3 and roots 4 and 1 is:
Answer: 113=53 (This is a false equation, meaning that both sides are not equal to each other)
Explanation: I’m not sure what your answer choices are but to get that answer I first rewrote the equation with the variable “m” replaced with 6 since m=6. Therefore it should be 18(6)+5=6(6)+17. Then I multiplied 18 by 6 to get 108, to then add 5 to get 113. Following that, i then multiplied 6 by 6 to get 36 then added 17 to get 53. The equation would then look like 113=53 when solved.
Answer:
65 square units
Step-by-step explanation:
The area of a triangle is: height times base divided by two.
So the area of one of the triangles is 10 square units.
multiply this times 4 to get the total area of the triangles
then add the area of the square which is 5 times 5
25 plus 40 = 65 square units
PLZ MARK BRAINLIEST
Thats true a number has to be greater than 1 and less than 10.
Answer:
105
Step-by-step explanation:
15*6=90
6*5=30
30/2=15
90+15=105
