Answer:
0.087
Step-by-step explanation:
Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:
= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:
X₅ ~ Poisson (20 (5/60))
X₅ ~ Poisson (1.6667)
Formula for computing probabilities for Poisson is as follows:
P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!
P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! = (e^-1.6667)((1.6667²)/3!)
P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)
P(X₅= 3) = (2.718^(-1.6667))0.46
P(X₅= 3) = 0.1889×0.46
P(X₅= 3) = 0.086894
P(X₅= 3) = 0.087
Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.
Answer:
y = 3
x = 1
y = 1.5
x = 2
Step-by-step explanation:
For the first x point, look at the graph where x is 0. When x is 0, y is 3. So the first one is 3. For the second one, there is a point on the graph where y is 4. Where y is 4, x is 1, so you the second answer is 1. For the third one, find the y point where x is -1. At the x value, -1, y is 1.5. For the last one, where y is 5, x is 2.
Answer:
Step-by-step explanation:
Graph is shifted 4 units to the right and reflected over the x-axis.
Step-by-step explanation:
is this the question you asked