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Zarrin [17]
3 years ago
10

Which three-dimensional object can be formed by rotating a rhombus about one of its diagonals?

Mathematics
1 answer:
Ghella [55]3 years ago
6 0
Shape 3 is the correct answer


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While looking at some reports, a store manager notes that televisions that retail for $475 and up costing customers $513 once th
Mekhanik [1.2K]

The sales tax percentage of the store manager report is 7.41%

<h3>How to solve for the sales tax percentage</h3>

Customers are subject to a charge known as sales tax when they buy goods and services.

It is a pass-through tax, which means you must collect it from clients and send the money to your state or local government. the seller do not contribute sales tax.

The sales tax is first calculated by

= price after tax - price before tax

= 513 - 475

= 38

sales tax percentage is calculated using the formula

= (Tax amount / Price before tax) × 100%

= (38 / 513) * 100

= 7.4074

= 7.41%

Learn more about sales tax at:

brainly.com/question/20220356

#SPJ1

3 0
1 year ago
Can someone help me please
dezoksy [38]
Lol i hope tou meant simplify

7 0
2 years ago
What's the difference between centimeters square centimeters
GalinKa [24]
Square centimeters are just telling that it's an area of a rectangle, square or some other shape.
8 0
3 years ago
Read 2 more answers
Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?
siniylev [52]

Answer:

\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}

Step-by-step explanation:

12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}

6 0
3 years ago
Which represents the solution(s) of the graphed system of equations, y = –x2 + x + 2 and y = –x + 3? (1, 2) (1, 2) and (0, 3) (–
max2010maxim [7]
Y = -x^2 + x + 2
y = -x + 3

-x + 3 = -x^2 + x + 2
x^2 - x - 2 - x + 3 = 0
x^2 -2x + 1 = 0
(x - 1)(x - 1) = 0

x - 1 = 0      y = -x + 3
x = 1           y = -1 + 3
                   y = 2

solutions are : (1,2) , (1,2)


5 0
3 years ago
Read 2 more answers
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