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zepelin [54]
3 years ago
7

Twelve education students, in groups of four, are taking part in a student-teacher program. Mark cannot be in the first group be

cause he will be arriving late.
How many ways can the instructor choose the first group of four education students?
220
330
1,980
7,920
Mathematics
2 answers:
aliya0001 [1]3 years ago
7 0
The answer is 330. Or answer B
Sati [7]3 years ago
7 0

yeah this is right its "B"

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Martha compra 2 kilos de tomate y 1 kilo de cebolla pagando S/ 8,40. Si la siguiente semana compra 1 kilo de tomate y 2 kilos de
Rashid [163]

Responder:

2,40

Explicación paso a paso:

Dado que:

Dejar :

Tomate = t

Cebolla = n

(2 kilo de t) + (1 kilo de n) = 8.40

(1 kilo de t) + (2 kilo de n) = 7.80

2t + n = 8,40 - - (1)

t + 2n = 7,80 - - (2)

De (2);

t = 7,80 - 2n

Ponga t = 7.80 - 2n en (1)

2 (7,80 - 2n) + n = 8,40

15,6 - 4n + n = 8,40

15,6 - 3n = 8,40

-3n = 8,40 - 15,6

-3n = - 7,2

n = 2,4

t = 7,80 - 2 (2,40)

t = 7,80 - 4,80

t = 3

Por lo tanto, el costo de 1 kilo de cebolla es 2,40

8 0
3 years ago
Vertical, Complementary and Linear Pair Angles
dlinn [17]
1) Vertical angles-the angles will equal each other.
8+7x=9x-4
12+7x=9x
12=2x
x=6
2) Supplementary-Angles will add up to 180
6+13x+7x+14=180
20+20x=180
20x=160
x=8
4 0
3 years ago
X+3y-2z=10, -x-2y+z=-7, 3x+9y-5z=28
NISA [10]
Hmm
what you do is try to eliminate 1 variable in 2 equaions first
we can elminate x's in first and 2nd equation

add first and 2nd equation
x+3y-2z=10
<u>-x-2y+z=-7 +</u>
0x+y-z=3
y-z=3


multiply 2nd equation by 3 and add to last one
-3x-6y+3z=-21
<u>3x+9y-5z=28 +</u>
0x+3y-2z=7

3y-2z=7

we now have
y-z=3
3y-2z=7
multiply first equation by -2 and add to 2nd

-2y+2z=-6
<u>3y-2z=7 +</u>
y+0z=1
y=1

now we can sub back
y-z=3
1-z=3
minus 1
-z=2
times -1
z=-2

sub baack into any equation
x+3(1)-2(-2)=10
x+3+4=10
x+7=10
minus 7
x=3

x=3
y=1
z=-2
(3,1,-2)

6 0
4 years ago
Read 2 more answers
The linear function graphed below represents Brenda’s monthly cell phone bill based on the number of hours she uses. What is her
Ierofanga [76]

Answer:

You didn't attach an image, can't exactly help. sorry!

3 0
3 years ago
How do i solve this problem?
Eduardwww [97]

I think the first numerator cant be Z so I solved the question assuming it is 2;

Answer:

(x,y,z)=(1,5,7)

Hope this helps.

7 0
3 years ago
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