**Answer:**

C. 49

**Step-by-step explanation:**

When you put the equation together it becomes: 7(9)-14=49

**Answer:**

15

**Step-by-step explanation:**

Let the probability of picking an orange = P(O), and the probability of picking a strawberry = P(S),

Based on the question, he picked an orange first and the probability of picking that is

**P(****O)**** ****=**** ****1****2****/****50**

Then he picked a strawberry on the second pick, the probability of picking the strawberry is **P(S)** and we'll find that later.

The probability of picking orange then strawberry with replacement is

**P(****O)**** ****×**** ****P(****S)**** ****=**** ****9****/****1****2****5**

Substitute the P(O)=12/50,

**1****2****/****5****0**** ****×**** ****P(****S)**** ****=**** ****9****/****1****2****5**

**P(****S)**** ****=**** ****3****/****10**

Then by finding the number of strawberry candies, we'll just have to multiply P(S) with the total number of candies, i.e.

**Number ****of ****strawberry ****candy**

**=**** ****3****/****10**** ****×**** ****50**

**=**** ****1****5**

We can first add up the cards so we know how many we have in all:

16 + 16 + 18 = 50 cards

We can do this a little bit easier if we get the "16"-cards in one number total.

16 + 16 = 32

= 32 x 2 =

50 x 2

= 64 : 2 = 32 %

100

We did just divide the % of two types cards on 2, so we get the %-chance of 1 type card.

I am not quite sure, but I think that 32 % is the correct answer.