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4 years ago

7

Twelve education students, in groups of four, are taking part in a student-teacher program. Mark cannot be in the first group be

cause he will be arriving late.
How many ways can the instructor choose the first group of four education students?
220
330
1,980
7,920

2 answers:

aliya0001 [1]4 years ago

7 0

The answer is 330. Or answer B

Sati [7]4 years ago

7 0

yeah this is right its "B"

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25+18 divided by 6-1

forsale [732]

40R3 it 40r3the answer is

8 0

3 years ago

Read 2 more answers

The income elasticity of the demand coefficient is for normal goods. Choose one:A. equal to zeroB. less than zero C. greater tha

katovenus [111]

Answer:

D. sometimes less than zero and sometimes greater than zero.

Step-by-step explanation:

The income elasticity of demand is the responsiveness of the increase in the consumers income versus the quantity of goods and services demanded in an economy. we have five types of income elasticity of demand which are namely high elasticity, unitary elasticity, low elasticity and negative elasticity.

in high elasticity of demand when income rises then we see a much bigger increase in the quantity of goods and services demanded therefore positive coefficient.

The unitary elasticity of demand is when the income increases at the same rate the quantity of goods and services demanded rises therefore a coefficient is constant.

the low elasticity of demand is when income increases at a lower rate than the increase in the quantity demanded. positive but low coefficient.

The negative elasticity of demand is when an income increases and the quantity decreases therefore a negative coefficient is seen.

4 0

3 years ago

Calculus 2. Please help

Anarel [89]

Answer:

$\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}}} \, dx = \infty$

General Formulas and Concepts:

<u>Algebra I</u>

Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

<u>Calculus</u>

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integrals

Definite Integrals

Integration Constant C

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

U-Solve

Improper Integrals

Exponential Integral Function: $\displaystyle \int {\frac{e^x}{x}} \, dx = Ei(x) + C$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx$

<u>Step 2: Integrate Pt. 1</u>

[Integral] Rewrite [Exponential Rule - Rewrite]: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \int\limits^1_0 {\frac{e^{-x^2}}{x} \, dx$
[Integral] Rewrite [Improper Integral]: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \int\limits^1_a {\frac{e^{-x^2}}{x} \, dx$

<u>Step 3: Integrate Pt. 2</u>

<em>Identify variables for u-substitution.</em>

Set: $\displaystyle u = -x^2$
Differentiate [Basic Power Rule]: $\displaystyle \frac{du}{dx} = -2x$
[Derivative] Rewrite: $\displaystyle du = -2x \ dx$

<em>Rewrite u-substitution to format u-solve.</em>

Rewrite <em>du</em>: $\displaystyle dx = \frac{-1}{2x} \ dx$

<u>Step 4: Integrate Pt. 3</u>

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {-\frac{e^{-x^2}}{x} \, dx$
[Integral] Substitute in variables: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {\frac{e^{u}}{-2u} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}\int\limits^1_a {\frac{e^{u}}{u} \, du$
[Integral] Substitute [Exponential Integral Function]: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(u)] \bigg| \limits^1_a$
Back-Substitute: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-x^2)] \bigg| \limits^1_a$
Evaluate [Integration Rule - FTC 1]: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-1) - Ei(a)]$
Simplify: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{Ei(-1) - Ei(a)}{2}$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \infty$

∴ $\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx$ diverges.

Topic: Multivariable Calculus

7 0

3 years ago

Hi, this is apart of my homework assignment!

Hunter-Best [27]

Answer:

Percent Change is 16%

The change is increased.

Step-by-step explanation:

The original amount = 25

Amount increase = 4

We need to find percent increase

The formula used is: $\frac{Amount \ increased}{Original \ Amount}*100$

Putting values in formula

$Percent \ Change = \frac{Amount \ increased}{Original \ Amount}*100\\Percent \ Change =\frac{4}{25}*100\\Percent \ Change =16 \%$

So, Percent Change is 16%

The change is increased.

5 0

3 years ago

A private club grew by 7 members each week for 63 weeks. What was the total change in the club's size? members

ikadub [295]

Answer:

The answer is 441

Step-by-step explanation:

7 x 63 = 441

5 0

3 years ago