Answer:
$127.80
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)
Answer:
The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
Suppose a sample of 333 tankers is drawn. Of these ships, 257 did not have spills.
333 - 257 = 76 have spills.
This means that 
80% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).
Answer:
-7/5 is the correct answer
The <em>correct answer</em> is:
The mean for July is smaller than the median; and
the mean for August is larger than the median.
Explanation:
A distribution with a positive skew would have a longer whisker in the positive direction than in the negative direction. A larger mean than median would also indicate a positive skew.
Alternatively, a distribution with a negative skew would have a longer whisker in the negative direction than in the positive direction. A smaller mean than median would also indicate a negative skew.
The whisker in the negative direction for July is longer than the whisker in the positive direction. This indicates a negative skew.
The whisker in the positive direction for August is longer than the whisker in the negative direction. This indicates a positive skew.
X would = 324/5 hope dis helped
