Answer:
Step-by-step explanation:
You are being asked to compare the value of a growing infinite geometric series to a fixed constant. Such a series will always eventually have a sum that exceeds any given fixed constant.
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<h3>a)</h3>
Angelina will get more money from the Choice 1 method of payment. The sequence of payments is a (growing) geometric sequence, so the payments and their sum will eventually exceed the alternative.
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<h3>c)</h3>
For a first term of 1 and a common ratio of 2, the sum of n terms of the geometric series is given by ...
Sn = a1×(r^n -1)/(r -1) . . . . . . . . . . series with first term a1, common ratio r
We want to find n such that ...
Sn ≥ 1,000,000
1 × (2^n -1)/(2 -1) ≥ 1,000,000
2^n ≥ 1,000,001 . . . . add 1
n ≥ log(1,000,001)/log(2) . . . . . take the base-2 logarithm
n ≥ 19.93
The total Angelina receives from Choice 1 will exceed $1,000,000 after 20 days.
Answer:
This is my guess...
"Even today, the need for work is a common reason people move to urban areas."
Step-by-step explanation:
The article talks about technology and how it lead to bigger cities in the past. Because we are reading about prior years, there is no need to talk about the present day.
Answer:
5^5
Step-by-step explanation:
when multiplying two expression like this you should add up their powers
in this case it's 2 + 3
Answer:
b = (d-c)/a
Step-by-step explanation:
ab+c=d
Subtract c from each side
ab+c-c=d-c
ab = d-c
Divide by a
ab/a = (d-c)/a
b = (d-c)/a