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3 years ago

100 POINTS!!!

Mathematics

1 answer:

ioda3 years ago

4 0

Answer: A. Standard Form

Standard form is Ax+By = C, where A,B,C are integers

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Evaluate 9!/6!3!<br><br> A: 1<br> B: 84<br> C: 68

Anika [276]

B, im hundred percent sure its right

8 0

3 years ago

In the year 2000, the population of a city was 600,000 citizens. The population increases at a rate of 1.8% per year.

Alona [7]

Y=600000(1+1.8%)^(x-2000)
So the population in 2012
Y=600,000×(1+0.018)^(2,012−2,000)
Y=743,232

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3 years ago

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A hospital cafeteria has 20

Virty [35]

Answer:

Step-by-step explanation:

So if their is 65% of 20 tables with 6 chairs that's 13 tables.

And if their is 35% of 20 tables with 4 chairs that's 7 tables.

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3 years ago

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Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v

olga_2 [115]

We are given

$f=z^3 -x^2y$

Firstly, we can find gradient

so, we will find partial derivatives

$f_x=0 -2xy$

$f_x=-2xy$

$f_y=0 -x^2$

$f_y=-x^2$

$f_z=3z^2$

now, we can plug point (-5,5,2)

$f_x=-2*-5*5=50$

$f_y=-(-5)^2=-25$

$f_z=3(2)^2=12$

so, gradient will be

$gradf=(50,-25,12)$

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

$|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}$

$|v|=\sqrt{29}$

now, we can find unit vector

$v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

now, we can find dot product to find direction of the vector

$dir=(gradf) \cdot (v')$

now, we can plug values

$dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

$dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })$

$dir=-\frac{248\sqrt{29}}{29}$ .............Answer

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3 years ago

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with the square root of negative 1 in the numerator (the top) and eight in the demominator (on bottom) what is the answer

AleksAgata [21]

-1^2/8 = 1/8 is the answer

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3 years ago