Solve this equation using a common base
1 answer:
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The subtraction of complex numbers is cos(π)+i sin(π).
Given [cos(3π/4+i sin(3π/4) and
=cos (π/2) +i sin(π/2)
We have to find the value of .
A complex number is a number that includes real number as well as a imaginary unit in which . It looks like a+ bi.
We have to first solve and then we will be able to find the difference.
[ cos (3π/4)+i sin (3π/4)]
[cos(π-π/4)+ i sin (π-π/4)]
= [-cos(π/4)+sin (π/4)]
=(-1/
+1/
)
=
=0
cos(π/2)+i sin (π/2)
=0+i*1
=1
Now putting the values of ,
=-1
=-1+i*0
=cos (π)+i sin(π)
Hence the value of difference between is cos(π)+i sin(π).
Learn more about complex numbers at brainly.com/question/10662770
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