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Len [333]
3 years ago
6

Which of the following compounds have the same empirical formula?

Chemistry
2 answers:
nadya68 [22]3 years ago
7 0
The empirical formula<span> of a chemical compound is the simplest positive integer ratio of atoms present in a compound. Therefore, the correct answer from the choices is the last option. </span><span>C7H14 and C10H20  have the same empirical formula which is CH2. Hope this answers the question.</span>
notka56 [123]3 years ago
3 0

<u>Answer:</u> The compounds having same empirical formula are C_7H_{14}\text{ and }C_{10}H_{20}

<u>Explanation:</u>

Empirical formula is defined as the formula in which atoms in a compound are present in simplest whole number ratios. The atoms in the compounds must be same.

For the given options:

  • <u>Option A:</u>  NO\text{ and }NO_2

Empirical formula of NO = NO

Empirical formula of NO_2=NO_2

Thus, they do not have the same empirical formula

  • <u>Option B:</u>  C_4H_{10}\text{ and }C_{10}H_4

Empirical formula of C_4H_{10}=C_2H_5

Empirical formula of C_{10}H_4=C_5H_2

Thus, they do not have the same empirical formula

  • <u>Option C:</u>  CO_2\text{ and }SO_2

Empirical formula of CO_2=CO_2

Empirical formula of SO_2=SO_2

Thus, they do not have the same empirical formula

  • <u>Option D:</u>  C_6H_{12}\text{ and }C_{6}H_{14}

Empirical formula of C_6H_{12}=CH_2

Empirical formula of C_{6}H_{14}=C_3H_7

Thus, they do not have the same empirical formula

  • <u>Option E:</u>  C_7H_{14}\text{ and }C_{10}H_{20}

Empirical formula of C_7H_{14}=CH_2

Empirical formula of C_{10}H_{20}=CH_2

Thus, they have the same empirical formula

Hence, the compounds having same empirical formula are C_7H_{14}\text{ and }C_{10}H_{20}

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In this experiment you will create solutions with different ratios of ethanol and water. What is the mole fraction of ethanol wh
Andrej [43]

Answer:

The mole fraction of ethanol is 0.6. A 10 mL volumetric pipette must be used for to measure the 10 mL of ethanol. The vessel should be clean and purged.

Explanation:

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3 years ago
what is the molarity of an HCI solution if 25.0 ml of 0.185 M NaOH is required to neutralize 0.0200 L of HCI?​
tekilochka [14]

Answer:

0.231 M.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid, HCl (nA) = 1

Mole ratio of the base, NaOH (nB) = 1

Next, the data obtained from the question:

Volume of base, NaOH (Vb) = 25 mL

Molarity of base, NaOH (Mb) = 0.185 M

Volume of acid, HCl (Va) = 0.0200 L

Molarity of acid, HCl (Ma) =?

Next, we shall convert 0.0200 L to mL

This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.0200 L = 0.0200 L × 1000 mL /1 L

0.0200 L = 20 mL

Thus, 0.0200 L is equivalent to 20 mL.

Finally, we shall determine the molarity of the acid solution as follow:

Mole ratio of the acid, HCl (nA) = 1

Mole ratio of the base, NaOH (nB) = 1

Volume of base, NaOH (Vb) = 25 mL

Molarity of base, NaOH (Mb) = 0.185 M

Volume of acid, HCl (Va) = 20 mL

Molarity of acid, HCl (Ma) =?

MaVa / MbVb = nA/nB

Ma × 20 / 0.185 × 25 = 1

Ma × 20 / 4.625 = 1

Cross multiply

Ma × 20 = 4.625 × 1

Ma × 20 = 4.625

Divide both side by 20

Ma = 4.625 / 20

Ma = 0.231 M

Thus, the molarity of the acid solution is 0.231 M.

3 0
3 years ago
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