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Elza [17]
3 years ago
6

For the following reaction, the products are favored at equilibrium. Classify each of the reactants and products based on their

strength as Bronsted Lowry acids or bases.
(C2H5)2NH + C6H5OH -> (C2H5)2NH2+ + C6H5O-

(C2H5)2NH

C2H5)2NH2

C6H5O-

C6H5OH

Match with the following.

a. Stronger Bronsted Lowry acid
b. Weaker Bronsted Lowry acid
c. Stronger Bronsted Lowry base
d. Weaker Bronsted Lowry base
Chemistry
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

(C2H5)2NH    -------------> c. Stronger Bronsted Lowry base

C2H5)2NH2+  ------------>  b. Weaker Bronsted Lowry acid

C6H5O-          ------------->  d. Weaker Bronsted Lowry base

C6H5OH       --------------->   a. Stronger Bronsted Lowry acid

Explanation:

Bronsted-Lowry defined an acid as a molecule or ion which donates a proton, while a base is a molecule or ion which accepts the proton. Bronsted-Lowry Theory of definition of an acid and base could also be extended to include acid-base titrations in non aqueous solution. In this theory, the reaction of an acid with a base constitutes the transfer of a proton from an acid to the base.

From the question given, we are to Classify each of the reactants and products based on their strength as Bronsted Lowry acids or bases:

(C2H5)2NH + C6H5OH    ⇄  (C2H5)2NH2+ + C6H5O-

(C2H5)2NH    -------------> c. Stronger Bronsted Lowry base

C2H5)2NH2+  ------------>  b. Weaker Bronsted Lowry acid

C6H5O-          ------------->  d. Weaker Bronsted Lowry base

C6H5OH       --------------->   a. Stronger Bronsted Lowry acid

In the forward reaction, Phenol (C6H5OH) donates a proton to diethylamine (C2H5)2NH which accepts it. The phenol behaves as an acid and the diethylamine behaves as a base.

In the backward reaction, diethylammonium(C2H5)2NH2+) ion donates a proton to the phenolate (C6H5O-), Therefore, diethylammonium behaving as an acid (proton donor) and the phenolate behaves as a base(proton acceptor)

The equilibrium of this reaction lies to the far right (which is indicated by the longer arrow of the forward reaction) because Phenol is a stronger Bronsted Lowry acid than the diethylammonium. (i.e Weaker Bronsted Lowry acid).

Similarly, the diethylamine is a stronger Bronsted Lowry base while the phenolate which is a weaker Bronsted Lowry base.

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A piece of aluminum weighing 10.0 grams is placed into a graduated cylinder that has an initial volume (before immersion) of 35.
padilas [110]

Answer:

The density of the metal sample is 2.70 \frac{grams}{mL}

Explanation:

Density is a magnitude that allows you to measure the amount of mass in a given volume of a substance. Then, the expression for the calculation of density is the ratio between the mass of a body and the volume it occupies:

d=\frac{m}{V}

Density, according to the International System of Units, is usually expressed in kilograms per cubic meter (kg / m3) or gram per cubic centimeter (g / cm3). Although it can also be expressed in any other unit of mass by volume.

So, for the calculation of density you know that:

  • mass of the sample= 10 grams
  • volume of the sample = volume on the cylinder after immersion - volume on the cylinder before immersion= 38.7 mL - 35.0 ml = 3.7 mL

Then:

d=\frac{10 grams}{3.7 mL}

d=2.70 \frac{grams}{mL}

<u><em>The density of the metal sample is 2.70 </em></u>\frac{grams}{mL}<u><em></em></u>

5 0
3 years ago
A 0.20 M solution of a weak acid has a pH of 5.40. What is the Ka for the acid?
sweet [91]

Answer:

The Ka for this weak acid is 7,92 * 10^-11

Explanation:

First of all, let's think the equation

HA + H2O <------> H3O+  +   A-

When we add water to a weak acid, it dissociates in an equilibrium to generate the corresponding anion and the hydronium cation  (the acid form of water)

How do you calculate Ka??  Ka is the acid equilibrium constant.

( [H3O+]  . [A-] ) / [HA] where all the concentrations are in equilibrium.

We don't have the concentration in equilibrium but we have the initial concentration. So...

 HA + H2O <------> H3O+  +   A-

initial- 0.2 M             I don't have H3O+, either A-

reaction - an specific amount reacted  (X)

in equilibrium (0,2 - X)  <----->  X   +  X

And now, how's the formula for Ka

( [H3O+]  . [A-] ) / [HA] = Ka

(X . X) / (0.2-X)

X^2 / (0.2-X) = Ka

Look, that we don't have X as the [H3O+] but we know the pH, so we can know the [H3O+] indeed.

10^-pH = [H3O+]

10^-5,40 = 3,98 * 10^-6

Let's go back to Ka

( [H3O+]  . [A-] ) / [HA] = Ka

(3,98 * 10^-6)^2 / (0.2 - 3,98 * 10^-6) = Ka

(3,98 * 10^-6 is an small number, soooo small that we can approximate to 0)

If we have in order 10^-6, 10^-5 we can consider that.

So now, we have

(3,98 * 10^-6)^2 / (0.2) = Ka

1,58 * 10^-11 / (0.2) = Ka = 7,92* 10^-11

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3 years ago
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4 years ago
What is a hypothesis
babunello [35]

a hypothesis is an idea or explanation that you then test through study and experimentation

3 0
4 years ago
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A 2.35 g sample of an unknown gas at 55 ∘C and 1.05 atm is stored in a 1.85 L flask.
lbvjy [14]

Answer:

Molar mass =  32.64 g / mol.

The density of gas is 1.3 × 10⁻³g/mL.

Explanation:

Given data:

Mass of sample = 2.35 g

Pressure = 1.05 atm

Volume = 1.85 L    (1.85 × 1000 = 1850 ml)

Temperature = 55 °C    (55+ 273.15 = 328.15 K)

Density = ?

Formula:

d = m/ v

The volume of flask would be the volume of gas.

d = 2.35 g / 1850 mL = 0.0013 g/mL or 1.3 × 10⁻³g/mL

The density of gas is 1.3 × 10⁻³g/mL.

Molar mass:

Now we will calculate the moles of a gas first in order to find the molar mass of a gas.

Formula:

PV =nRT

n = number of moles.

n = PV / RT

n = 1.05 atm × 1.85 L / 0.0821 atm. dm³. K⁻¹ . mol⁻¹ × 328.15 K

n = 1.9425 atm . L / 26.941115 atm . dm.³mol⁻¹

n = 0.072 mol

Now we will find the molar mass.

Number of moles = mass / molar mass

0.072 mol = 2.35 g / molar mass

Molar mass = 2.35 g / 0.072 mol

Molar mass =  32.64 g / mol

8 0
3 years ago
Read 2 more answers
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