Question

if 26.8g of copper (ll) chloride are dissolved in sufficient water to make 4.00 L of solution, what is the molarity of the solution? & what is the solvent?

Answer 1

Answer: Molarity of the solution is $4.97 \times 10^{-2} M$ and water is the solvent.

Explanation:

Given: Mass of solute = 26.8 g

Volume = 4.00 L

Now, moles of copper (II) chloride (molar mass = 134.45 g/mol) are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{26.8 g}{134.45 g/mol}\\= 0.199 mol$

Molarity is the number of moles of a substance divided by volume of solution in liter.

Therefore, molarity of given solution is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.199 mol}{4.00 L}\\= 0.04975 M\\= 4.97 \times 10^{-2} M$

Solvent is defined as a component which is present in higher amount in a solution. Generally, a solvent is present in liquid state but it can also be a solid or gas.

In the given solution, copper (II) chloride is dissolved in water so copper (II) chloride is the solute and water is the solvent.

Thus, we can conclude that molarity of the solution is $4.97 \times 10^{-2} M$ and water is the solvent.