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Andreyy89
3 years ago
13

PLS SEE ATTACHMENT! NEED HELP!!!

Mathematics
2 answers:
marta [7]3 years ago
8 0
Find it out yourself goodbye and goodnight or good morning
pshichka [43]3 years ago
6 0

Answer:idk

Step-by-step explanation:

idk

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In Maryland, the sales tax is 6%. If you buy a shirt for $38, how much is the tax?
scoundrel [369]

Answer:

$2.28

38x.06

Brainlyest Pls

3 0
3 years ago
Geometry help please! Match the reasons with the statements.
SSSSS [86.1K]

Given:

∠PRS and ∠VUW are supplementary.

To prove:

Line TV || Line QS

Solution:

Step 1: Given

∠PRS and ∠VUW are supplementary.

Step 2: By the definition of supplementary angles

m\angle {PRS}+m\angle {VUW}=180^{\circ}

Step 3: Angles forming a linear pair sum to 180°

m\angle {PRS}+m\angle {SRU}=180^{\circ}

Step 4: By transitive property of equality

step 2 = step 3

m\angle {PRS}+m\angle {VUW}=m\angle {PRS}+m\angle {SRU}

Step 5: By algebra cancel the common terms in both side.

{m} \angle {VUW}={m} \angle{SRU}

Step 6: By converse of corresponding angles postulate

Line TV || Line QS

Hence proved.

6 0
3 years ago
Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini
Nat2105 [25]
By inspection, it's clear that the sequence must converge to \dfrac32 because

\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32

when n is arbitrarily large.

Now, for the limit as n\to\infty to be equal to \dfrac32 is to say that for any \varepsilon>0, there exists some N such that whenever n>N, it follows that

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|

From this inequality, we get

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}
\implies|2n-1|>\dfrac5{2\varepsilon}
\implies2n-1\dfrac5{2\varepsilon}
\implies n\dfrac12+\dfrac5{4\varepsilon}

As we're considering n\to\infty, we can omit the first inequality.

We can then see that choosing N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that N\in\mathbb N.
6 0
3 years ago
A recipe for four dozen cookies requires 1 1/2 cups of flour. How much flour is needed for one dozen cookies ?
Arada [10]
1 1/2 cups = 3/2. 3/2 divided by 4 = 3/2 x 1/4 = 3/8 cup
4 0
2 years ago
Dana wants to make cookies. The recipe calls for 2/3 cups of flour for two dozen. She only wants to make one dozen,so how much f
Veseljchak [2.6K]

Answer:

1/3 c flour

Step-by-step explanation:

divide 2/3 in half because you're going from 2 dozen to 1 dozen

2/3 ÷ 2 equals 2/3 x 1/2 which equals 1/3

3 0
3 years ago
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