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3 years ago

A compact disc is designed to last an average of 4 years with a standard deviation of 0.8 years.

Mathematics

2 answers:

aniked [119]3 years ago

8 0

3-4/.8=1.25
then use the probability z chart to get
10.56%

Naya [18.7K]3 years ago

7 0

Answer:

10.56%

Step-by-step explanation:

Step 1: Use the z formula

The z-formula is

$z=\frac{x-mean}{standard | deviation}$

$z=\frac{3-4}{0.8} \\\\z=\frac{-1}{0.8} \\\\=-1.25$

P(z < -1.25)

Step 2: Use a p chart to find -1.25

-1.25 on a p chart is .1056

there is a 10.56% chance that a CD will last less than 3 years.

The answer is 10.56%

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The number 10^100 is called a googol. What kind of number is a googol? Select all correct answers.

lana66690 [7]

Answer: a, b, c, d

Step-by-step explanation: its not a fraction, its a integer, its positive, and is rational (every integer is rational).

7 0

3 years ago

Given the quadratic function f(x) = 4x^2 - 4x + 3, determine all possible solutions for f(x) = 0

solong [7]

Answer:

The solutions to the quadratic function are:

$x=i\sqrt{\frac{1}{2}}+\frac{1}{2},\:x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:4x^2\:-\:4x\:+\:3$

Let us determine all possible solutions for f(x) = 0

$0=4x^2-4x+3$

switch both sides

$4x^2-4x+3=0$

subtract 3 from both sides

$4x^2-4x+3-3=0-3$

simplify

$4x^2-4x=-3$

Divide both sides by 4

$\frac{4x^2-4x}{4}=\frac{-3}{4}$

$x^2-x=-\frac{3}{4}$

Add (-1/2)² to both sides

$x^2-x+\left(-\frac{1}{2}\right)^2=-\frac{3}{4}+\left(-\frac{1}{2}\right)^2$

$x^2-x+\left(-\frac{1}{2}\right)^2=-\frac{1}{2}$

$\left(x-\frac{1}{2}\right)^2=-\frac{1}{2}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{1}{2}=\sqrt{-\frac{1}{2}}$

$x-\frac{1}{2}=\sqrt{-1}\sqrt{\frac{1}{2}}$ ∵ $\sqrt{-\frac{1}{2}}=\sqrt{-1}\sqrt{\frac{1}{2}}$

$\sqrt{-1}=i$

$x-\frac{1}{2}=i\sqrt{\frac{1}{2}}$

Add 1/2 to both sides

$x-\frac{1}{2}+\frac{1}{2}=i\sqrt{\frac{1}{2}}+\frac{1}{2}$

$x=i\sqrt{\frac{1}{2}}+\frac{1}{2}$

also solving

$x-\frac{1}{2}=-\sqrt{-\frac{1}{2}}$

$x-\frac{1}{2}=-i\sqrt{\frac{1}{2}}$

Add 1/2 to both sides

$x-\frac{1}{2}+\frac{1}{2}=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

$x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

Therefore, the solutions to the quadratic function are:

$x=i\sqrt{\frac{1}{2}}+\frac{1}{2},\:x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

4 0

2 years ago

For brainly and points

Anna [14]

Answer:

Step-by-step explanation:

Given

$\frac{2}{3}$ m + 5 = 17 ( subtract 5 from both sides )

$\frac{2}{3}$ m = 12 ( multiply both sides by 3 to clear the fraction )

2m = 36 ( divide both sides by 2 )

m = 18 → C

6 0

3 years ago

Pentagon DEFGH is translated 4 units to the right to create pentagon UVXYZ. DE is 5cm long. What is the length of UV?

Semmy [17]

If a shape is translated (has it's vertex' coordinates moved/changed), then it retains its original values but just has different vertex coordinates.

Thus since DE is equal to UV, then,

DE = UV; substitution:
5=5

3 0

3 years ago

For 12-13, use the figure. A bike path crosses a road as shown. Solve for each indicated angle or variable.

Volgvan

Answer:

x=21° and ∠KMH=96°

Step-by-step explanation:

From the given information that a bike path crosses a road and the given figure, we get

∠GMH=∠KMI=84°(Vertically opposite angles)

⇒4x=84°

⇒x=21°

therefore, the value of ∠GMH=4x=4(21)=84°

Now, ∠KMH+∠KMI=180°( Linear pair)

⇒∠KMH+84°=180°

⇒∠KMH=180-84

⇒∠KMH=96°

Thus, the value of ∠KMH is 96°

6 0

2 years ago