Hannah and anthony are siblings who have ages that are consecutive odd integers. The sum of their ages is 92. Which equations co
1 answer:
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Answer: a) 79.10 % b) 7% c)19.85 %
Step-by-step explanation:
a) Z = ( × - μ ) ÷ σ Where μ mean of population σ standard deviation Z is the abscissa to give the area or probability we are looking for associated to the value 10 ounces ( × )
So: Z = ( 10 - 9 ) ÷ 1.2 ⇒ Z = 1/1.2 ⇒ Z = 0.83 it has to be below this value
From Z tables we get P [ Z ≤ 0.82 ] = 0.7910 0r 79.10 %
b) Following the same procedure: We look for
P [ Z > ( x - μ ) ÷ σ ] ⇒ Z = ( 12 -10 ) ÷ 1.2 = 2.5
From Z table we get the area under the curve from the left tail up to the point Z < 2.5 ( 2.5 not included) but we were asked for the area out of that previous so 1- 0.9930 = 0.007 is the area we are looking for
So P (b) = 0.007 or 7 %
Finally between the two points above mentioned ( 10 ≤ Z ≤ 12 ) we use the previous values (taking in consideration the limits, according to the problem statement )
Z ≤ 10 Z ⇒( 10-9 ) ÷ 1.2 Z = 0.7967
Z ≥ 12 Z ⇒ ( 12 - 9 ) ÷ 1.2 Z = 0.9952
The interval is between these two points
0.9952 - 0.7967 = 0.1985 ⇒ or 19.85 %
The attached help in the understanding of the solution
Hello Shannonrodrigue. You can solve this by setting up an exponential growth equation.
Now we solve for b
![\sqrt[4]{\frac{6}{5}} = \sqrt[4]{b^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B6%7D%7B5%7D%7D%20%3D%20%5Csqrt%5B4%5D%7Bb%5E4%7D)
![\sqrt[4]{\frac{6}{5}} = b](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B6%7D%7B5%7D%7D%20%3D%20b)
Now that we have found b, we can use the equation
to predict how many bacteria will be present after 10 hours.
![b = \sqrt[4]{\frac{6}{5}}](https://tex.z-dn.net/?f=b%20%3D%20%5Csqrt%5B4%5D%7B%5Cfrac%7B6%7D%7B5%7D%7D)
t = 10
![A = 3000\sqrt[4]{\frac{6}{5}}^{10} = 4732.3228 = 4732](https://tex.z-dn.net/?f=A%20%3D%203000%5Csqrt%5B4%5D%7B%5Cfrac%7B6%7D%7B5%7D%7D%5E%7B10%7D%20%3D%204732.3228%20%3D%204732%20)
Answer = 4732
Now we solve for b
Now that we have found b, we can use the equation
t = 10
Answer = 4732