Answer:
Step-by-step explanation:
Let the actual width of belt be x
we are given that the ideal width of safety belt strap is 5 cm
So, Difference between actual and ideal = (x-5)cm
We are also given that An actual width can vary by at most 0.35 cm.
So, The difference between actual and ideal width should be less than or equal to 0.35 cm
So, 
We know
and 
and 
and 
So,
Hence the range of acceptable widths is
Y(initial) = 9
V(initial) = 168
V(final) = 0
g(accel-grav) = 32 (in feet per second
squared)
Use the following equation:
V(final) = V(initial) + a(t)
Since this object is moving straight up and
down, a = -32
Enter the knowns into the equation
0 = 168 - 32t
32t = 168
t = 168/9.8
t = 5.25
Now that you know the time it takes to
reach it's maximum, use the general
kinematics equation to solve for final
distance:
y(final) = y(initial) + V(initial)(t) + (1/2)a
(t²)
y(final) = 9 + 168(5.25) + (1/2)(-32)
(5.25²)
= 9 + 882 - 441
= 450 feet
Answer:10 presents fell off
Step-by-step explanation: to find 2/6 we can start with finding 1/6 because it’s easier. To do that we divide 30 by 6 which equals 5. because 5 is 1/6 5x2 is 2/6 so the answer is 10
Let x and x+1 be the two consecutive integers.
Then their sum is x + (x+1) = 2x + 1.
0.166 as a percent is 16.6%!
I hope this helped. :)
Please give me brainliest if I am correct!
