The answer is C Radius because look o. the outside it's clearly bigger
Given:
The given terms are
and 
To find:
The common factors of given terms.
Solution:
We have,
and 
The factor forms are


The common factors are 2, p, m, n, n. So,
Common factors = 
= 
Therefore, the common factor of given terms is
.
Power= work/time, work/time=(force x displacement)/time
therefore, power= (Fd)/t
The number of combinations is the product of the number of choices for each selection...
c=11*10*49*48*47*46=559,352,640