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miv72 [106K]
3 years ago
15

Subtract -2k3 + k2 - 9 from 5k3 - 3k + 7.

Mathematics
2 answers:
tankabanditka [31]3 years ago
8 0
5k3-3k+7-(-2k3+k2-9)
basically rewrite with simple algebra principles
15k-3k+7-(-6k+2k-9)
split up the parenthesis
15k-3k+7+6k-2k+9
sort them
15k-3k+6k-3k+7+9
short down by adding up the similar factors
answer: 18k+18
factorise
18(k+1)
both forms are right
Sever21 [200]3 years ago
7 0

Answer:  The required value is 7k^3-k^2-3k+16.

Step-by-step explanation:  We are given to subtract the polynomial -2k^3+k^2-9 from 5k^3-3k+7.

That is, we need to find the value of S, where

S=(5k^3-3k+7)-(-2k^3+k^2-9)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To perform the given subtraction, we need to combine the like terms as follows :

S\\\\=(5k^3-3k+7)-(-2k^3+k^2-9)\\\\=5k^3-3k+7+2k^3-k^2+9\\\\=(5+2)k^3-k^2-3k+(9+7)\\\\=7k^3-k^2-3k+16.

Thus, the required value is 7k^3-k^2-3k+16.

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Please help me out!​
seropon [69]

Answer:

Second option

Third option

Fourth option

Step-by-step explanation:

We have the following quadratic function

f(x) =(x-1)(x+7)

Use the distributive property to multiply the expression

f(x) =x^2+7x-x-7

f(x) =x^2+6x-7

For a function of the form f (x) = ax ^ 2 + bx + c the x coordinate of the vertex is:

x =-\frac{b}{2a}

Then in this case the coordinate of the vertex is:

x =-\frac{6}{2(1)}

x =-3

To obtain the y coordinate of the vertex we evaluate the function at x = -3

f(-3) =(-3)^2+6(-3)-7

f(-3) =9-18-7

f(-3) =-16

Then the vertex is:  (-3, -16)

We can see in the graph that the zeros of the function are x=1 and x=-7

Then the function is decreasing from -∞ to -3 and then it is increasing from -3 to ∞

The function is positive for x and x> 1

The correct answers are:

Second option

Third option

Fourth option

7 0
3 years ago
a. What is the area and circumference of circle P? Explain how you calculated this answer. b. If the arc measure of arc COD is 1
Vikki [24]

Answer:

a) 9*π or approx 28.26

b) ∡CRB=100°

Step-by-step explanation:

As known for secants crossing each other inside the circle is coorect the following:

BR*RD=AR*RC

=> 3*RD=4*4.5

RD=6

The diameter of the circle with center P is BD=BR+RD=3+6=9

So the radius of the circle is D/2=9/2=4.5

As known the circumference of any circle can be calculated as

C=2*π*r  , where r is the circle's  radius

So C=2*4.5*π=9*π= approx   3.14*9=28.26

b) ∡CRB=∡ARD= (arcBC+arcAD),  where arcBC and arcAD smaller arcs

BD is the circle's  diameter, so arc BD=180°

So arcBC=180°-arcCOD=180°-100°=80°

Similarly arcBD=180°

arcAD=180°-arcBSA=180°-60°=120°

∡CRB= (80°+120°)/2=100°

5 0
3 years ago
The sum of the reciprocals of two consecutive odd integers is 24/143. find the two integers.
nordsb [41]
Let one integer be x, the consecutive odd integer is x+2
reciprocals are 1/x and 1/(x+2)
1/x +1/(x+2)=24/143
make the denominators the same:
(x+2)/[x(x+2)] +x/[x(x+2)]=24/143
143(2x+2)=24(x)(x+2)
286x+286=24x²+48x
24x²-238x-286=0
use the quadratic formula: x=22 this doesn't work because 22 is not an odd number.
or x=-2.1666666666 (this is not an integer)

weird.
4 0
3 years ago
Find the slop of the line​
Goshia [24]

Answer:

5/4 is your slope.

Step-by-step explanation:

5-0= 5

4-0= 4

slope is chang in y over change in x. Your first point is (0,0) and you second is (4,5).

6 0
3 years ago
Simplify 3a-3b/3a+12b
Lena [83]
If it is a fraction like (3a-3b)/(3a+12b)
= [3(a-b)]/[3(a+4b)]
= (a-b)/(a+4b)
6 0
3 years ago
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