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miv72 [106K]
3 years ago
15

Subtract -2k3 + k2 - 9 from 5k3 - 3k + 7.

Mathematics
2 answers:
tankabanditka [31]3 years ago
8 0
5k3-3k+7-(-2k3+k2-9)
basically rewrite with simple algebra principles
15k-3k+7-(-6k+2k-9)
split up the parenthesis
15k-3k+7+6k-2k+9
sort them
15k-3k+6k-3k+7+9
short down by adding up the similar factors
answer: 18k+18
factorise
18(k+1)
both forms are right
Sever21 [200]3 years ago
7 0

Answer:  The required value is 7k^3-k^2-3k+16.

Step-by-step explanation:  We are given to subtract the polynomial -2k^3+k^2-9 from 5k^3-3k+7.

That is, we need to find the value of S, where

S=(5k^3-3k+7)-(-2k^3+k^2-9)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To perform the given subtraction, we need to combine the like terms as follows :

S\\\\=(5k^3-3k+7)-(-2k^3+k^2-9)\\\\=5k^3-3k+7+2k^3-k^2+9\\\\=(5+2)k^3-k^2-3k+(9+7)\\\\=7k^3-k^2-3k+16.

Thus, the required value is 7k^3-k^2-3k+16.

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The National Center for Health Statistics (NCHS) reports that 70%70% of U.S. adults aged 6565 and over have ever received a pneu
Marianna [84]

Answer:

11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they received a pneumococcal vaccination, or they did not. The probability of an adult receiving a pneumococcal vaccination is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of U.S. adults aged 65 and over have ever received a pneumococcal vaccination.

This means that p = 0.7

20 adults

This means that n = 20

Determine the probability that exactly 12 members of the sample received a pneumococcal vaccination.

This is P(X = 12).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{20,12}.(0.7)^{12}.(0.3)^{8} = 0.1144

11.44% probability that exactly 12 members of the sample received a pneumococcal vaccination.

3 0
3 years ago
List P contains m numbers; list Q contains n numbers. If the two lists are combined to produce list R, containing m + n numbers,
Anarel [89]

Answer: YES

Step-by-step explanation:

We need to write out the expressions

P= {m}

Q= {n}

R= {m+n}

If 2m=n then we can say;

P= {½n} Q= {n} & R= {³/²n}

It is obvious that the smaller number in Q is greater than the largest number in P

We can make some assumptions.

Let n= (x,y,z)

Consequently,

P={½x,½y,½z} Q={x,y,z} and R= {1.5x,1.5y,1.5z}

Therefore the median will be the middle element,

Median of P= ½y

Median of Q = y

Median of R = 1.5y

And 1.5y>1.5y

Then we can agree that the median of R is greater than the median of both P and Q

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3 years ago
Lucy drinks 5 cups of coffee. Doctor said to cut down by 75%. How many ounces of coffee is she allowed per day?
UkoKoshka [18]
The answer is Lucy should be allowed to drink 1.25 ounces a day.
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3 years ago
Find the measure of the angle plz help
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Answer:

you need a protractor to measure it. They have made a picture of that too.

Step-by-step explanation:

you need a protractor to measure it. They have made a picture of that too.

4 0
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The correct answer is C. The hyphae absorb nutrition and detect when conditions are right to sprout a mushroom above ground.

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Moreover, these two features are exemplified by mushroom (fungi) in the sentence "The hyphae absorb nutrition and detect when conditions are right to sprout a mushroom above ground" because the first section shows the developing mushroom takes nutrients from the soil or its environment and this is essential for growing and survival. Also, the second section of the sentence shows the developing mushroom can sense its environment and respond by developing only in appropriate conditions.

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