X= 1, x = 5
-3|x - 3| = -6
———— —– divide both sides by -3
-3 -3 and remove the bars
x - 3 = 2
+3 +3
—————
x = 5⭐️
-3|1-3|➡️-3|-2|= -6
The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
Read more about exponential functions at:
brainly.com/question/11464095
#SPJ1
If 3 is the bold number then the answer is D. <span>#TeamAlvaxic</span>
Answer:
im fairly certain the answer is C
Step-by-step explanation:
you take the base problem, 9-4n and plug in a number for n each time. 9-4(1), 9-4(2), 9-4(3)…
3/5 squared in 9/25, 3*3/5*5 :)
