(2t^(3)+3t-4)-(4t^(2)-6t)

Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a rand

SOVA2 [1]

Answer:

Question 1:

(a) P(x<60) = 0.9236

(b) P(x>16) = 0.9564

(c) P(16<x<60) = 0.88

(d) P (x>60) = 0.0764

Question 2:

(a) P(x<3) = 0.0668

(b) P(x>7) = 0.0062

(c) P(3<x<7) = 0.927

Step-by-step explanation:

Question 1:

x = no. of mg of porphyrin per deciliter of blood.

μ = 40

σ = 14

(a) We need to compute P(x<60). We need to find the z-score using the normal distribution formula:

z = (x - μ)/σ

P(x<60) = P((x - μ)/σ < (60 - 40)/14)

= P(z < 20/14)

= P(z<1.43)

Using the normal distribution probability table we can find the value of p at z=1.43.

P(z<1.43) = 0.9236

so, P(x<60) = 0.9236

(b) P(x>16) = P(z>(16-40)/14)

= P(z>-1.71)

= 1 - P(z<-1.71)

= 1 - 0.0436

P(x>16) = 0.9564

(c) P(16<x<60) = P((16-40)/14) < x < (60-40)/14)

= P(-1.71 < z < 1.43)

This probability can be calculated as: P(z<1.43) - P(z<-1.71)

P(16<x<60) = 0.9236 - 0.0436

P(16<x<60) = 0.88

(d) P(x>60) = 1 - P(x<60)

we have calculated P(x<60) in part (a) so,

P(x>60) = 1 - 0.9236

P (x>60) = 0.0764

Question 2:

μ = 4.5 mm

σ = 1.0 mm

In this question, we will again compute the z-scores and then find the probability from the normal distribution table.

(a) P(x<3) = P(z<(3-4.5)/1)

= P(z<-1.5)

P(x<3) = 0.0668

(b) P(x>7) = 1 - P(x<7)

= 1 - P(z<(7-4.5)/1)

= 1 - P(z<2.5)

= 1 - 0.9938

P(x>7) = 0.0062

(c) P(3<x<7) = P(x<7) - P(x<3)

we have computed both of these probabilities in parts (a) and (b) so,

P(3<x<7) = 0.9938 - 0.0668

P(3<x<7) = 0.927

6 0

2 years ago

Find the maximum profit and the number of units that must be produced and sold in order to yield the maximum profit. Assume that

V125BC [204]

Answer:

-1.39

Step-by-step explanation:

Revenue and cost as a function of units sold are $u(x) = 9x-2x^{2}$ and $c(x)=x^{3}-3x^{2}+4x+1$ respectively.

we are have to know for which value or input units are these functions at maximum which translates to for how many units is the revenue maximum and for how many same units is our cost minimum.

5 0

3 years ago

Multiply (2.0 ⋅ 10−4) ⋅ (3.1 ⋅ 10−20). Express the answer in scientific notation. The options are:

Mkey [24]

(2.0×10^-4)×(3.1×10^-20)
=(2.0×3.1)×(10^4×10^-20)
=6.2×10^(-4+(-20))
=6.2×10^-24. Hope it help!

3 0

2 years ago

What is w in w(w-6)=0?

Romashka-Z-Leto [24]

The answer for your question is 6

5 0

3 years ago

The population of Smallville can be found by the equation Pt) = le", where P(t) is the

pashok25 [27]

Answer:

The population of the town in the year 1962 will be 1730.

Step-by-step explanation:

The population of Smallville can be found by the equation $P(t) = Ie^{rt}$ , where P(t) is the population at time t, r represents the rate of growth, and I is the initial population.

Now, if there are 225 residents in 1950 and the population of the town grows at a rate of 17% per year, then the population of the town in the year 1962 will be $P(12) = 225 e^{0.17 \times 12} = 1730$ (Approximate)

7 0

3 years ago