The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
Answer:
69.08
Step-by-step explanation:
circumference is 2πr which is 3.14 x 2 x 11
Answer:
<h3>Sv is angle bisector of rst.</h3>
Answer:
- 3, - 11, - 35, - 107
Step-by-step explanation:
Using the recursive formula with f(1) = - 3 , then
f(2) = - 2 + 3f(1) = - 2 + 3(- 3) = - 2 - 9 = - 11
f(3) = - 2 + 3f(2) = - 2 + 3(- 11) = - 2 - 33 = - 35
f(4) = - 2 + 3f(3) = - 2 + 3(- 35) = - 2 - 105 = - 107
Thus the first four terms are
- 3, - 11, - 35, - 107
