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Vesnalui [34]
3 years ago
12

What is the monthly payment rate for a $20,000 loan for 4 years with an annual interest rate of 4.8%

Mathematics
1 answer:
yarga [219]3 years ago
5 0

Answer:

96048

Step-by-step explanation:

times 20000 by 4.8 then times 4 by 12 and add your answers

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Find the equation of the line with slope m = 5/3 that contains the point (-6, -12)
Mice21 [21]

Answer:

3y-(-12) = 5(x-(-6)

3y+12= 5(x+6)

3y +12 = 5x + 30

3y = 5x +30 - 12

3y = 5x + 18

y = 5x + 6

4 0
3 years ago
Which line is perpendicular to the line y = -3x + 2?
AleksAgata [21]
I'm pretty sure the answer is C
3 0
3 years ago
There are 87 first graders in after care.after 39 students are picked up, the teacher put the remaining students into 4 groups f
Elden [556K]

Answer:

There are 12 students in each group

Step-by-step explanation:

87-39= 48

48/4= 12

Hope this helped. ;)

5 0
4 years ago
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Help! how can i determine the range
djverab [1.8K]

Answer:

[-1,\infty)

Step-by-step explanation:

Remember that the range is the set of all y-values. Thus, since the minimum of the function is y=-1, then our range is [-1,\infty). In interval notation, we use brackets to show what's included and parentheses to show what's not included.

3 0
3 years ago
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businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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