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3 years ago

What is the monthly payment rate for a $20,000 loan for 4 years with an annual interest rate of 4.8%

Mathematics

1 answer:

yarga [219]3 years ago

5 0

Answer:

96048

Step-by-step explanation:

times 20000 by 4.8 then times 4 by 12 and add your answers

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Which phrase best describes the translation from the group y=2x^2 to the graph of y= 2x^2 +5

dsp73

Answer:

The graph move up 5.

Step-by-step explanation:

When we add a constant to the end of a parabola, it shifts the graph up and down. Since the constant here is positive, the graph moves up by that number (5)

7 0

3 years ago

In a race, 47 out of the 50 swimmers finished in less than 35 minutes. What percentage of the swimmers finished the race less th

Dmitry [639]

Answer:

94%

47*2=94

50*2=100

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$