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marissa [1.9K]
3 years ago
10

A batter hits a fly ball into the outfield. The

Physics
2 answers:
Anon25 [30]3 years ago
6 0
Answer: gravitational force
Vaselesa [24]3 years ago
4 0
The gravitational force :))))
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Please help me with these questions... I really need help..
attashe74 [19]
45) B) Vaporizing water at its boiling point

46) D) There is no change in temperature 

47) B) Molecules must be pulled apart

48) D) Steam at 100 C

Hope this helps!
6 0
3 years ago
Problem 24.3 The assembly is made from a steel hemisphere, rho st = 7. 80 Mg/m3 , and an aluminum cylinder, rho al = 2. 70 Mg/m3
AlladinOne [14]

Answer:

0.12 m    

Explanation:

The mass of the steel hemisphere is:

m_h=\rho_s\times \frac{2}{3}\pi r^2\\m_h = 7.8\times 10^3 \times \frac{2}{3}\pi (0.16)^2\\m_h=66.9 kg

Mass of the aluminium cylinder is:

m_c=\rho_a\times \pi r^2 h\\m_c=2.7\times 10^3 \times \pi (0.08)^2(0.18) \\m_c =9.7 kg

mass center of steel hemisphere from the bottom:

z_1=r-3r/8\\z_1=0.16-(3\times 0.16/8) =0.1 m

mass center of aluminium cylinder from the bottom:

z_2=r+h/2 \\z_2=0.16+0.18/2=0.25 m

center of mass is

Z=\frac{m_hz_1+z_2m_c}{m_s+m_c}\\Z=\frac{66.9\times 0.1+9.76\times 0.25}{66.9+9.76} = 0.12 m

3 0
2 years ago
Help on 9 and 10!!!!!! I’ll give 5 starts
julia-pushkina [17]

Answer: part a is e

part b a  

Explanation:

I HOPE THIS HELPS

4 0
2 years ago
A funnel-shaped low pressure closure
cupoosta [38]
What is the rest ?? What about the funnel shaped low pressure closure??

6 0
3 years ago
After a plant or animal dies the 14C content decreases with a half-life of 5730 years. If an archaeologist finds an ancient fire
Shalnov [3]

Answer:

age of the site is 15411.75 years old

Explanation:

Given data

plant or animal dies = 14C

time period = 5730 year

carbon = 15.5%

to find out

age (in years) of the ancient site

solution

we know that Final value = Initial value  × 0.5^{n}

here n is half life passed

so for 15.5%

15.5% = 100% of  0.5^{n}

0.155 = 1 × 0.5^{n}

now take log both side

log 0.155 = log  0.5^{n}

n = log 0.155 / log 0.5

n = 2.68966

we know here  5730 years in half life

so for 2.68966 half-lives = 2.68966 × 5730  =  15411.7518

age of the site is 15411.75 years old

6 0
3 years ago
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