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Agata [3.3K]
2 years ago
12

A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter a

t a speed of 6.0 meters/second. What is the emf produced?
Physics
2 answers:
avanturin [10]2 years ago
8 0
<span>The answer to your question is choice: D</span>
MrRissso [65]2 years ago
4 0

Answer: answer on Plato is D

Explanation:

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The velocity of an object includes its speed and what
SCORPION-xisa [38]
I believe that the correct answer you are looking for is the distance traveled 

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Which type of energy is stored in a capacitor? electric potential energy chemical energy gravitational energy heat energy
Tom [10]

Energy stored in a capacitor is Electric Potential Energy. Capacitor is device used for storing energy. The work done to charge is a capacitor is stored in it in the form of Electrical potential energy. Electrical potential energy is defined as capacity to do work due to the position change. For example, we know fans have capacitor installed in it. When we turn off the fan, it continue moving using the electrical energy stored in the capacitor.

6 0
2 years ago
If the resistance is not changed but the voltage is increased, what happens to the current
julsineya [31]

We know that According to Ohm's Law :

Current passing through a Conductor is directly proportional to the Voltage over a given Resistance.

⇒ V ∝ I

⇒ V = I × R

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6 0
3 years ago
if a current of 0.3 ampere flows through a conductor of resistance of 11.7 ohm's,the voltage across the ends of the conductor is
Gnesinka [82]

Here,

Resistance = 11.7

Ampere = 0.3

Voltage = ?

Now,

R = V/A

11.7 = V/0.3

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7 0
2 years ago
Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it
erica [24]

<u>Answer:</u>

2N/cm

<u>Step-by-step explanation:</u>

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

F=kx

where, F is the force which is stretching or compressing the spring,

k is the spring constant; and

x is the distance the spring is stretched.

Substituting the given values to find the elastic constant  k to get:

F=kx

4=k(2)

k=\frac{4}{2}

k=2

Therefore, the elastic constant is 2 Newton/cm.

5 0
3 years ago
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