$950 x.10 = 1002.24
I think it’s right
Answer:
Picture of the problem? I can't solve without
Given that 3 ties were selected and the probability of selecting a bow tie is 3%, the probability of selecting 3 bow ties will be:
P(selecting 3 ties)=P(selecting a bow tie)*P(selecting a bow tie)*P(selecting a bow tie)
=(0.03)*(0.03)*(0.03)
=0.000027
Answer:
It does not have a direct variation, because y doesnt vary directly with x
Step-by-step explanation:
Hope This Helps!!!
Answer:
0.2684 is the probability that the temperature reading is between 0.50 and 1.75.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 0 degrees
Standard Deviation, σ = 1 degrees
We are given that the distribution of thermometer readings is a bell shaped distribution that is a normal distribution.
Formula:
![z_{score} = \displaystyle\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
P(Between 0.50 degrees and 1.75 degrees)
![P(0.50 \leq x \leq 1.75)\\\\ = P(\displaystyle\frac{0.50 - 0}{1} \leq z \leq \displaystyle\frac{1.75-0}{1})\\\\ = P(0.50 \leq z \leq 1.75)\\= P(z \leq 1.75) - P(z < 0.50)\\= 0.9599 - 0.6915 = 0.2684 = 26.84\%](https://tex.z-dn.net/?f=P%280.50%20%5Cleq%20x%20%5Cleq%201.75%29%5C%5C%5C%5C%20%3D%20P%28%5Cdisplaystyle%5Cfrac%7B0.50%20-%200%7D%7B1%7D%20%5Cleq%20z%20%5Cleq%20%5Cdisplaystyle%5Cfrac%7B1.75-0%7D%7B1%7D%29%5C%5C%5C%5C%20%3D%20P%280.50%20%5Cleq%20z%20%5Cleq%201.75%29%5C%5C%3D%20P%28z%20%5Cleq%201.75%29%20-%20P%28z%20%3C%200.50%29%5C%5C%3D%200.9599%20-%200.6915%20%3D%200.2684%20%3D%2026.84%5C%25)
0.2684 is the probability that the temperature reading is between 0.50 and 1.75.