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sergiy2304 [10]
3 years ago
7

If the area of the rectangle shown is 150 square feet, we can use the equation 2x2 - 5x = 150 to find its dimensions. If the sol

ution to the equation is x = 10, what are the dimensions of the rectangle? A) 2 ft x 75 ft B) 5 ft x 30 ft C) 10 ft x 15 ft D) 15 ft x 20 ft
Mathematics
1 answer:
laiz [17]3 years ago
4 0
What does the 2x2 mean?
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Least fraction from least to greatest 8/9, 17/29,14/29,9/29
aniked [119]
17/29, 14/29, 9/29, 8/9 Hope this helps
7 0
3 years ago
Read 2 more answers
Plz explain properly, I have this on my MATH FINAL TMR
Nonamiya [84]
You are to calculate the # of students, based upon the starting volume of juice and the amount each student receives.

                                                     22 1/2 cups
This # of students is equal to ------------------------------
                                                [1 1/4 cup / student ]

and this could be found easily by dividing 22.5 by 1.25:  18.  There are 18 students.

6 0
3 years ago
Can someone please help me figure this out??
faltersainse [42]

Okay, first of all, you are probably stuck and don't understand what an exterior angle is. I don't know how to explain it but the exterior angle in this case is ∠DAB.

<h2>∠DAB = ∠ABC + ∠BCA</h2><h2>            = 90° + 62°</h2><h2>= 152°</h2><h2 /><h2>They said that the exterior angle was instead 128 degrees. This means that now the sum of the angles of B and C are 152 degrees, or, 152 - 128 = 34 degrees greater.</h2>
8 0
4 years ago
Find the length of the curve x=e^t e^{-t},\;\;y=5-2t,\;\;0 \le t \le 3.
Oksana_A [137]
\begin{cases}x(t)=e^t+e^{-t}\\y(t)=5-2t\end{cases}\implies\begin{cases}x'(t)=e^t-e^{-t}\\y'(t)=-2\end{cases}

The length of the curve is given by the integral

\displaystyle\int_0^3\sqrt{(e^t-e^{-t})^2+(-2)^2}\,\mathrm dt

Expand and rewrite the integrand:

(e^t-e^{-t})^2+(-2)^2=e^{2t}+2+e^{-2t}
=e^{-2t}(e^{4t}+2e^{2t}+1)
=e^{-2t}(e^{2t}+1)^2
\implies\sqrt{(e^t-e^{-t})^2+(-2)^2}=\dfrac{e^{2t}+1}{e^t}

Now the integral is

\displaystyle\int_0^3\dfrac{e^{2t}+1}{e^t}\,\mathrm dt=\int_0^3(e^t+e^{-t})\,\mathrm dt
=2\displaystyle\int_0^3\cosh t\,\mathrm dt
=2\sinh t\bigg|_{t=0}^{t=3}
=2\sinh 3
7 0
3 years ago
What is the domain of the function shown in the table. X {3, 5, 7, 9} Y {-4, -3, 3, 4}
zhenek [66]

Answer:3,5,7,9

Step-by-step explanation:I’m pretty sure all the inputs are the domains

7 0
2 years ago
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