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Fiesta28 [93]
2 years ago
14

I NEED HELP WITH THIS Q1

Mathematics
2 answers:
motikmotik2 years ago
7 0

Answer:

other guy is right

Step-by-step explanation:

levacccp [35]2 years ago
4 0

Answer:

\frac{1}{4} (x-5)=13

Step-by-step explanation:

So when we multiply this is what we get:

\frac{x-5}{4}=13

then we multiply the 4 by 13:

x-5=52

then after that we add 52+5 and we get:

x=57\\

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Lelu [443]
<span>The annual depreciation expense is $9,000, calculated as follows Cost of the asset is $80,000 less $8,000 salvage value which reduces the cost to $72,000. Useful life is 8 years. To determine annual depreciation expense using straight-line method, divide asset cost of $72,000 by 8 years of useful life equals $9,000 per year.</span>
6 0
3 years ago
Conditional Distribution, Marginal Distribution, Joint Distribution. <br> What’s the difference?
lutik1710 [3]

Explanation:

Marginal distribution: This distribution gives the probability for each possible value of the Random variable ignoring other random variables. Basically, the values of other variables is not considered in the marginal distribution, they can be any value possible. For example, if you have two variables X and Y, the probability of X being equal to a value, lets say, 4, contemplates every possible scenario where X is equal to 4, independently of the value Y has taken. If you want the probability of a dice being a multiple of 3, you are interested that the dice is either 3 or 6, but you dont care if the dice is even or odd.

Conditional distribution: This distribution contrasts from the previous one in the sense that we are restricting the universe of events to specific condition for other variable, making a modification of our marginal results. If we know that throwing a dice will give us a result higher than 2, then to in order to calculate the probability of the dice being a multiple of 3 using that condition, we have two favourable cases (3 and 6) from 4 total possible results (3,4,5 and 6) discarding the impossible values (1 and 2) from this universe since they dont match the condition given (note that the restrictions given can also reduce the total of favourable cases).

The joint distribution calculates the probabilities for two different events (related to two different random variables) occuring simultaneously. If we want to calculate the joint probability of a dice being multiple of 3 and greater than 2 at the same time, our possible cases in this case are 3 and 6 from 6 possible results. We are not discarding 1 or 2 as possible results because we are not assuming, that the dice is greater than 2, that is another condition that we should met in the combination of events.

3 0
3 years ago
Are expressions equivalent to 3(62)?
Brrunno [24]

Answer:

186

Step-by-step explanation:

4 0
3 years ago
Solve the system of equations Algebraically.
grandymaker [24]
Since y=x+3 (given)
Put value of y in equation x+y=(-3)
x+x+3=(-3)
2x=(-6)
x=(-3)
Put x=(-3) in x+y=(-3)
(-3)+y=(-3)
y=0
So, x=(-3)
y=0
4 0
3 years ago
Help plz will give brainliest
jolli1 [7]

Answer:  5(13.5-4.5)

5(9)

=45

6 0
3 years ago
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