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2 years ago

I NEED HELP WITH THIS Q1

Mathematics

2 answers:

motikmotik2 years ago

7 0

Answer:

other guy is right

Step-by-step explanation:

levacccp [35]2 years ago

4 0

Answer:

$\frac{1}{4} (x-5)=13$

Step-by-step explanation:

So when we multiply this is what we get:

$\frac{x-5}{4}=13$

then we multiply the 4 by 13:

$x-5=52$

then after that we add 52+5 and we get:

$x=57\\$

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PLEASE HELP ME WITH THIS LAST QUESTION

NemiM [27]

Answer:

1) 28

2) 22

3) 6

4) Skewed right

5) 17

Step-by-step explanation:

have a nice day :3

8 0

3 years ago

The arithmetic sequence a_ia i a, start subscript, i, end subscript is defined by the formula: a_1 = 15a 1 =15a, start subsc

daser333 [38]

Answer:

-1,512,390

Step-by-step explanation:

Given

a1 = 15

$a_i = a_{i-1} -7$

Let us generate the first three terms of the sequence

$a_2 = a_{2-1}-7\\a_2 = a_1 - 7\\a_2 = 15-7\\a_2 = 8$

For $a_3$

$a_3 = a_{3-1}-7\\a_3 = a_2 - 7\\a_3 = 8-7\\a_3 = 1$

Hence the first three terms ae 15, 8, 1...

This sequence forms an arithmetic progression with;

first term a = 15

common difference d = 8 - 15 = - -8 = -7

n is the number of terms = 660 (since we are looking for the sum of the first 660 terms)

Using the formula;

$S_n = \frac{n}{2}[2a + (n-1)d]\\$

Substitute the given values;

$S_{660} = \frac{660}{2}[2(15) + (660-1)(-7)]\\S_{660} = 330[30 + (659)(-7)]\\S_{660} = 330[30 -4613]\\S_{660} = 330[-4583]\\S_{660} = -1,512,390$

Hence the sum of the first 660 terms of the sequence is -1,512,390

6 0

3 years ago

Dean put together first boxes for 5 of his neighbors. Each box cost $1.00 and contained a plant and a $3.00 pair of gardening gl

Scorpion4ik [409]

(5 Neighbors) x (($1.00 Box) + (? Plant) + ($3.00 Gloves)) = 42.50

5 x (1 + x + 3) = 42.50

Combine in parens.

5 x (4 + x) = 42.50

Distribute.

20 + 5x = 42.50

Subtract 20 from both sides.

5x = 22.50

Divide both sides by 5.

x = 4.50

Thats the cost of each plant.

Check.

5 x (1 + 4.50 + 3)

5 x 8.50 = 42.50

3 0

3 years ago

Find the average of e^-x over [0,3]

yaroslaw [1]

The average value of a continuous function f(x) over an interval [a, b] is given by the integral,

$\displaystyle \frac1{b-a}\int_a^b f(x)\,\mathrm dx$

Compute the integral for f(x) = e ⁻ˣ over [0, 3] :

$\displaystyle \frac1{3-0}\int_0^3e^{-x}\,\mathrm dx=\frac13(-e^{-x})\bigg|_0^3=\frac13(-e^{-3}-(-e^{-0})) = \frac13 \left(1-\frac1{e^3}\right) = \boxed{\frac{e^3-1}{3e^3}}$

8 0

3 years ago

Plz help what’s the answer

Maslowich

Answer:

a. 192 b.60 c. 184, 164, 350

Step-by-step explanation:

a.Total of males=88+104

b.Female, Anaerobic=156-96

c. aerobic= 88+96=184

anaerobic=104+60

total=192+158

8 0

3 years ago