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shutvik [7]
3 years ago
5

2 numbers a and B are graphed on a number line is it always sometimes or never true

Mathematics
1 answer:
prohojiy [21]3 years ago
4 0
The answer is "sometimes".

 

If A = 3 and B = 1 then, A > B and A-B < A+B

 

On the other hand, If A = 3 and B = -1, then A > B but A-B is not less than A+B.  

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Explain how to write 50000 using exponents
Yakvenalex [24]
I think i need a bit more information but assuming if this is what you are looking for:

to write 50,000 in exponent form look for its multiples other than 1 and itself and then go from there.

This is what i general do, i pick a divisible number and keep dividing till i get to one.


50,000/2 = 25,000
25,000/5 = 5,000
5,000/10 = 500
500/10 = 50
50/10 = 5
5/5 = 1
so i divided by 2, 5,10, 10, 10, and 5 (three 10s, two 5s and one 2)

then i look if these numbers can be written in smaller divisible numbers (i.e. 10 is 2 and 5)

so 2, 5, (2,5), (2,5) ,(2,5), and 5 as you can see that cannot be divided into smaller numbers so we have thus five 5s and four 2s

therefore 50,000 = 5^5 x 2^4

hope this helps :P

(P.S. it is the best way i can explain online without a whole course on this)

3 0
3 years ago
A math tutor charges $30 per session each month plus a $5 scheduling fee. If jane pays a total of $215 in May for tutoring devic
wel

Answer:

it should be 6 not 100% sure though

Step-by-step explanation:

6 0
3 years ago
Solve the inequality<br> -1/3h ≥ 7<br> A. h ≥ –21<br> B. h ≤ 7 1/3<br> C. h ≤ –21<br> D. h ≥ -2 1/3
JulsSmile [24]
The Answer Is C Fam...................
8 0
3 years ago
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Need help<br> Question in the screenshot below<br> NO spam<br> Please show your work
Alja [10]
<h3>Answer:   x = 6</h3>

======================================================

Work Shown:

\log_{4}(x+10)+\log_{4}(x-2)=\log_{4}(64)\\\\\log_{4}\left((x+10)(x-2)\right)=\log_{4}(64)\\\\(x+10)(x-2)=64\\\\x^2-2x+10x-20=64\\\\x^2-2x+10x-20-64=0\\\\

x^2+8x-84=0\\\\(x+14)(x-6)=0\\\\x+14=0 \ \text{ or } \ x-6=0\\\\x=-14 \ \text{ or } \ x=6\\\\

Those are the possible solutions, but plugging x = -14 back into the original equation will lead to an error. So we rule x = -14 out

x = 6 works as a solution however

3 0
3 years ago
Help me plz asap if you can
Andrej [43]
Your answer for this is 17 hope i helped
8 0
3 years ago
Read 2 more answers
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