Prove the divisbility of the following numbers.
1 answer:
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Question:
The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both decreased by 2, the fraction is now equal to .
If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?
5n = 3d and n - 2 = 2d - 4
5n = 3d and 2n - 4 = d - 2
3n = 5d and 2n - 4 = d - 2
Answer:
5n = 3d and 2n – 4 = d – 2
Solution:
Let n be the numerator of the fraction and d be the denominator of the fraction.
Given the numerator and denominator of a fraction are in the ratio of 3 to 5.
This can be written as n : d = 3 : 5.
⇒ – – – – (1)
Do cross multiplication, we get
⇒ 5n = 3d
When the numerator and denominator are decreased by 2, the fraction is equal to .
⇒
Do cross multiplication, we get
⇒ 2(n –2)=1(d – 2)
⇒ 2n – 4 = d – 2
Hence, 5n = 3d and 2n – 4 = d – 2 can be used to solve the problem.
Answer: The quotient is (2x+1)
Step-by-step explanation:
Here, the dividend =
Divisor =
By the long division method for finding the quotient we will follow the following steps,
Steps 1 : Write dividend inside the division sign and divisor outside the division sign,
Step 2: Multiply the divisor by 2x and subtract the result by the dividend,
Step 3: Now, again multiply the divisor by 1,
Step 4: Subtract the result by the remaining dividend,
Since, further division is not possible,
Hence, the sum of all terms that are multiplied = 2x+1
Which is our quotient.
