Question

Which divisor of -2x^3 - 5x^2 + 4x - 2 results in a remainder of -14

Answer 1

Answer:

$f(x) = -2x^3 -5x^2 +4x -2\\option 1 : x+2 \\f(-2) = -2(-2)^3 -5(-2)^2 +4(-2)-2 = 16 -20-8-2= -14\\\\\\option 2: x+3\\f(-3) = -2(-3)^3 -5(-3)^2 +4(-3) - 2 = 54 -45 -12-2 = -5\\\\option 3: x-2\\f(2) = -2(2)^3-5(2)^2-4(2)-2=-16 -20-8-2=-46\\\\option4 :x-3\\f(3) = -2(3)^3 - 5(3)^2-4(3)-2 = -54-45-12-2=-113$

option 1: x + 2