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Maurinko [17]
3 years ago
7

What is the area of a rectangle with vertices (-8, -2), (-3,-2).(-3,-8), and (-8, -B)?

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0

Answer:

Area = 20

As B = -4

Where -3-1 = -4

We look at x for first measure = -8 -3 = 5

We look at y first sequence change for second measure = -B

x/y = -3-8 /-8 + B

= -3-8 = -8(-8)+B

B = -3+B = -3+1

B= -3+1 = -4

Second measure = -8-4 = 4

Therefore, using both measures in bold : the Area = 4 x 5  = 20  

Step-by-step explanation:

den301095 [7]3 years ago
6 0

Answer:

The area of the rectangle would be 20 square units.

Step-by-step explanation:

The distance between the points (-8, -2) and (-3,-2) is 5. This is the length of the rectangle.  The distance between (-3,-6) and (-3,-2) is 4. This is the width of the rectangle. To find the area, multiply the length and the width to get the 20 square units as the area.

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Answer:

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Step-by-step explanation:

Let's start by tking each subject and putting them in decimal form, so that way we have an accurate way to see which is truly greater.

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You now have the numbers .16, .13, .28, .07, .21, and .15

Just put these in order and you get:

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3 years ago
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Try this option:
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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