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Alexus [3.1K]
3 years ago
12

Find the mean of the data set 31,31,22,28,23?

Mathematics
2 answers:
Vikentia [17]3 years ago
6 0

27 because you add them all together and get 135 and divide that by how many numbers there are which is 5 and you get 27:)


Lina20 [59]3 years ago
3 0
The mean is 27 
How you do this is you add all the numbers together even the ones that are duplicated like in this case 31. Now add em all up which equals 135. Now you take the number that they equal up to and divide by how many numbers are in the set of data in this case it is 5. After dividing you get 27.
I hope this helps!
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seraphim [82]

Answer:

To solve for n you need to get it by itself

First you want to distribute your 2 through the (3n+14)

-2n+6n+28=-20 (2*3n+2*14= 6n+28)

Now you want to combine any like terms if possible

4n+28=-20 (-2n+6n=4n, both like terms)

Then you want to subtract -28 from both sides

4n=-48 (28-28=0, -20-28=-48)

Lastly you want to divide both sides by 4

n=-12 (4n/4=n, -48/4= -12)

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Answer:

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Step-by-step explanation:

Since we know she gets $1,600 as a base, and $60 <em>each book</em>, we have to add a variable to 60 to show how many books she sells. Your first equation will be P (which is the total) = 1,600 + 60N. Now, we have to replace N with 29. You now have P = 1,600 + 60(29) = 1,600 + 1,740 = $3,340. That's your answer!

5 0
3 years ago
Read 2 more answers
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azamat

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Svet_ta [14]

Answer:

\frac{(6q-5)}{(3q+5)}

Step-by-step explanation:

Given: \frac{18q^{2}-45q+25 }{9q^{2}-25 }

Factorizing the numerator and the denominator, we have:

18q^{2} - 45q + 25 = 18q^{2} - 30q - 15q + 25

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So that,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}

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Therefore,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(6q-5)}{(3q+5)}

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