Answer:
14.4 lb
Step-by-step explanation:
In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.
The torque generated by the child is:
T1 = 60 * 3 = 180 lb*feet
So, the torque generated by the weight needs to be higher than T1 in order to lift the child.
The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.
So, we have that:
T2 = 180 = mass * 12.5
mass = 180/12.5 = 14.4 lb
So the lowest weight is 14.4 lb
11 ⅓ gallons.
Explanation:
Since she sold 3⅓ gallons more on Sunday than she did on Saturday, you need to add 10⅔+3⅓. ⅓+⅔=3/3, or 1. 10+3=13, and 13+1=14. She sold 14 gallons on Sunday.
On Monday, she sold 2⅔ less than she did on Sunday, so we need to do 14-2⅔. 14-2 is 12, and 12-⅔= 11⅓. This means that she sold 11⅓ gallons on Monday.
Hope this helps :)
The student is wrong in not putting a parenthesis between 1/3 and x. An equation of a line has a general equation of y = mx + b where m is the slope and b is the y-intercept. In this case, most likely 1/3 is the slope and 0 is the y-intercept. However, writing the equation like that seems like the x variable is a denominator and if that is the case the equation will not represent a line already.
Step-by-step explanation:
The equation has 100, which represents the cost of the printer, then you add to .05p which stands for each page is .05 and you multiply it by p which would be the amount of pages, so when you do .05p it stands for the equation to to calculate the total cost of pages. Then .25p is the cost times the amount of pages.
Hope this helps, you understand it more.
The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.
Step-by-step explanation:
The given is,
The sum of two numbers is 21
The second number is six times the first number
Step:1
Let, m - First number
n - Second number
Step:2
From given,
n - 6m ( The second number is six times the first number )
Equation becomes,
Sum = m + n
Where,
21 = m + ( 6m )
21 = 7m
m = 3
Substitute m value n becomes,
n = 6m
= (6 × 3)
n = 18
Result:
The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.
