3 years ago

What is the measure of b if a=20 and c=29. using the pythagorean theorem

2 answers:

5 0

Since a^2+b^2=c^2 becomes 20^2+b^2=29^2, we solve for b:

400+b^2=841

b^2=441

b=21

So the length of b is 21 units.

Hope this helped!

vekshin13 years ago

4 0

Answer:

Step-by-step explanation:

b=21

a Leg

c Hypotenuse

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Lelu [443]

Answer:

$\frac{n^{2}}{2a}$

Step-by-step explanation:

Just split it up first $\frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}$
Then 9 divided by 18 can be simplified into the fraction 1/2
What can go into $a$ and $a^2$ ? a itself right, so if you divide a by a you get 1, if you divide $a^2$ by a you get a
Same as the a fraction, if you divide $n^3$ by n you get $n^2$
$\frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}=\frac{1}{2}\times \frac{1}{a} \times\frac{n^2}{1}=\frac{n^{2}}{2a}$