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3 years ago

How do I find the range?

Mathematics

2 answers:

Thepotemich [5.8K]3 years ago

6 0

Just remember, the range is all real values of y that you can get by plugging real numbers into x.

lara [203]3 years ago

3 0

By doing something like 56 lowest and 89 highest then do 89-56 the range us 33

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Solve for x. −32>−5+9x Enter your answer, as an inequality, in the box.

Elan Coil [88]

+5 to both sides
9x<-27
divide both sides by 9
x<-3

4 0

3 years ago

Can someone help me please

Taya2010 [7]

Answer:

n = -1

Step-by-step explanation:

n^2 + 5n + 1 = 3n

N^2 +2n +1 = 0 (subtract 3n from both sides)

(n+1)(n+1) = 0 (factor

n+1 =0; n= -1

n+1 = 0 ; n=-1

4 0

3 years ago

Which of the following is a vertical shift of the function f(x)=−(2)x up by 2 units?

expeople1 [14]

Answer:

-(2)x+2

Step-by-step explanation:

g(x)=F(x)+2

g(x)=-(2)x+2

3 0

3 years ago

19 + 11 - 12² ÷ 3 (12 - 9) · 11)) - 7 =

katovenus [111]

PEMDAS = Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

First, subtract the numbers in the parentheses, then multiply by 11.

(12 - 9) = (3)

3 x 11 = 33

19 + 11 - 12^2 ÷ 3(33) - 7

Now, just multiply 33 by 3, and then square 12 (12 x 12).

19 + 11 - 144 ÷ 99 - 7

Now, you can divide 144 by 99, this is an infinite number, so..

144 ÷ 99 = 1.455

19 + 11 - 1.455 - 7

Finally add, then subtract.

30 - 1.455 - 7

28.545 - 7

The final answer is 21.545.

7 0

3 years ago

23% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and as

zlopas [31]

Answer:

a) There is a 29.42% probability that the number of college students who say they use credit cards because of the rewards program is exactly two.

b) There is a 41.37% probability that the number of college students who say they use credit cards because of the rewards program is more than two.

c) There is a 69.49% probability that the number of college students who say they use credit cards because of the rewards program is between two and five, inclusive.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this exercise using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

10 students are randomly selected, so $n = 10$ .

23% of college students say they use credit cards because of the rewards program. This means that $\pi = 0.23$

(a) exactly two

This is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942$

There is a 29.42% probability that the number of college students who say they use credit cards because of the rewards program is exactly two.

(b) more than two

This is $P(X > 2)$ .

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities of these events must be 1. So:

$P(X \leq 2) + P(X > 2) = 1$

$P(X > 2) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{10,0}.(0.23)^{0}.(0.77)^{10} = 0.0733$

$P(X = 1) = C_{10,1}.(0.23)^{1}.(0.77)^{9} = 0.2188$

$P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0733 + 0.2188 + 0.2942 = 0.5863$

$P(X > 2) = 1 - P(X \leq 2) = 1 - 0.5863 = 0.4137$

There is a 41.37% probability that the number of college students who say they use credit cards because of the rewards program is more than two.

(c) between two and five inclusive.

This is

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942$

$P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343$

$P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225$

$P(X = 5) = C_{10,3}.(0.23)^{5}.(0.77)^{5} = 0.0439$

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.2942 + 0.2343 + 0.1225 + 0.0439 = 0.6949$

There is a 69.49% probability that the number of college students who say they use credit cards because of the rewards program is between two and five, inclusive.

8 0

3 years ago