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sveta [45]
3 years ago
14

A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, o

ne main course and two different desserts for their meal, how many different meals are possible?
A. 120
B. 240
C. 480
D. 600
E. 1200
Mathematics
1 answer:
Naddika [18.5K]3 years ago
8 0

Answer: E. 1200

Step-by-step explanation:

Given : A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts.

i.e. No. of choices for different salads= 8  -----(1)

No. of choices for different main courses = 5  ----(2)

No. of choices for different desserts = 6

When we choose two different desserts then we use permutation(repeatition not allowed) :

^6P_2=\dfrac{6!}{(6-2)!}=\dfrac{6\times5\times4!}{4!}=6\times5=30----(3)

[∵ No. of ways to choose r things out of n =^nP_r=\dfrac{n!}{(n-r)!} ]

If customers choose one salad, one main course and two different desserts for their meal , then By Fundamental principle of counting (Multiply (1) , (2) and (3)), the number of  different meals are possible :-

8\times5\times30\\\\=1200

Hence, the correct answer is E. 1200 .

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Delicious77 [7]

The correct next step Amy could take is to factor (x^2 - 16) on the left side of the equation to yield (x + 4)(x – 4)(x + 2) = 0.

The equation is given as:

\mathbf{(x^2 - 16)(x + 2) = 0}

The possible next steps are:

1. Expand the equation as follows

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2. Express x^2 -16 as a difference of two squares as follows

\mathbf{(x + 4)(x- 4)(x + 2) = 0}

However, the correct step in this case is to factor x^2 - 16 as a difference of two squares to give \mathbf{(x + 4)(x- 4)(x + 2) = 0}

This is so, because the question says Amy is trying to solve for variable x.

This step will ensure that she gets the possible values of x, unlike expanding the whole equation .

Hence, the correct next step is \mathbf{(x + 4)(x- 4)(x + 2) = 0}

Read more about equations at:

brainly.com/question/7674413

7 0
2 years ago
1/2 + 5/3 - 1<br>------------------<br> 3/4
Sav [38]
Hey there :)

\frac{ \frac{1}{2}+ \frac{5}{3} -1 }{ \frac{3}{4} }
      ↓ Is the same as
\frac{1}{2} + \frac{5}{3} -1 ÷ \frac{3}{4}

Since it is a division by fraction, we can multiply by what is called the reciprocal
( The attached picture might help you )
( \frac{1}{2} + \frac{5}{3} - 1 ) × \frac{4}{3} 
     ↓ For this part, we need the common denominator, which is 6
\frac{1(3)}{2(3)}+ \frac{5(2)}{32)}  \frac{1(6)}{1(6)} × \frac{4}{3}

\frac{3}{6}+ \frac{10}{6}  - \frac{6}{6} × \frac{4}{3}
\frac{7}{6} × \frac{4}{3}
\frac{14}{9} =  1\frac{5}{9}
  ↑
Your final answer
 

7 0
3 years ago
Plz help if you can<br> Thank ya
koban [17]

Answer:

90\pi

Step-by-step explanation:

The first step is to find the slant height of the cone. Using the pythagorean theorem, you can find that \sqrt{12^2+5^2}=13 cm. Plugging this into the equation, you get \pi \cdot 5 \cdot 13=90\pi. Hope this helps!

3 0
3 years ago
I need help on 13 and 15 that all
mihalych1998 [28]
<span>Anna learns in her science class that the human eye blinks an average of 4,200,000 times a year. What is this number expressed in scientific notation?</span>
8 0
3 years ago
Write an equation for the line that is parallel to y = 2x + 6 and passes through (-1,5).
Fantom [35]

Answer:

y=2x+7

Step-by-step explanation:

A linear equation is typically organized in the form y=mx+b, where m is the slope of the line and b is the y-intercept (the y-coordinate of the point on the line that crosses the y-axis).

Parallel lines <em>always</em> have the same slope. When we examine the given equation, y=2x+6, we can identify immediately that 2 is in the place of m, the slope. This means that the slope of the line we're trying to solve for is also 2. So far, our equation looks like this:

y=2x+b

The last thing we need to calculate is b, the y-intercept. We can do this by plugging in the given point (-1,5) as x and y.

y=2x+b

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Add 2 to both sides to isolate b

5+2=-2+b+2

7=b

Now that we know b, we plug that into our original equation and now we have a final equation of:

y=2x+7

I hope this helps!

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3 years ago
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