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andriy [413]
3 years ago
5

A bathtub is filling with water at a rate of 60 liters per minute.

Mathematics
1 answer:
Phoenix [80]3 years ago
7 0
60t is your answer

Have a good day
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Log(x+3)(2x+3)+log(x+3)(x+5)=2
trasher [3.6K]
<span>log(x-3)+log(x) = 2 + log(x+2) 
---------------------------
log[(x-3)x] - log(x+2) = 2
-----
log[(x^2-3x)/(x+2)] = 2
----
(x^2-3x)/(x+2) = 2^2
-------

x^2-3x = 4x+8
x^2 - 7x - 8 = 0
Factor:
(x-8)(x+1) = 0
Positive solution:
x = 8</span>
4 0
3 years ago
Solve the equation w/2.5 = 9.
inessss [21]

Answer:

w=45/2 or 22.5

Step-by-step explanation:

i hope this helps :)

8 0
2 years ago
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kendra needs 1/3 cup of nuts for a cake she ia baking .if she had 8 cups of nuts how many cakes could she make
Stella [2.4K]

Answer:

2 2/3

Step-by-step explanation:

well needs  1/3 cups for a cake and she only has 8 cups, so just multiply,

1/3x8=2 2/3

8 0
3 years ago
Researchers are studying the distribution of subscribers to a certain streaming service in different populations. From a random
Katen [24]

Answer:

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

Step-by-step explanation:

Given

n = 200

x_1 = 34 -- City C

x_2 = 54 --- City K

Required

Determine the 90% confidence interval

This is calculated using:

CI = \bar x \± z\frac{\sigma}{\sqrt n}

Calculating \bar x

\bar x = \bar x_1 - \bar x_2

\bar x = \frac{x_1}{n} - \frac{x_2}{n}

\bar x = \frac{34}{200} - \frac{54}{200}

\bar x = 0.17 - 0.27

For a 90% confidence level, the ​z-score is 1.65.  So:

z = 1.65

Calculating the standard deviation \sigma

\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }

So:

\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }

\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}

So:

CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}

CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}

7 0
3 years ago
What is the value of x?
Anna007 [38]

Answer:

4x= 40

Step-by-step explanation:

40/4 = 10

7 0
3 years ago
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