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Anastasy [175]
3 years ago
13

Tuition for one year at the state university Nick would like to attend is about $18,000. Nick plans to save money each month for

the next 4 years to help pay for his first year. If his parents plan to contribute $12,000 toward his first year, what is the minimum about Nick must save each month to have enough money to pay for his first year of tuition? A) $50 B) $75 C) $125 D) $250
Mathematics
2 answers:
klemol [59]3 years ago
6 0

Answer:

The answer isn't D, it's C. I don't know why a verified answer is wrong, and I don't know how people are saying it's correct. I almost failed my test because of the "verified" answer above.

Step-by-step explanation:

1. Subtract 12,000 from 18,000 (6,000).

2. Since there are 12 months in each year and he's saving money each month for 4 years, multiply 12 and 4 (48).

3.  Divide 6,000 by 48 (125).

Therefore, the answer is C. 125.

Lady bird [3.3K]3 years ago
5 0

18,000-12,000=6,000

12 months x 4 = 48

6,000 / 48= $125


so the answer is D

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Step-by-step explanation:

R = 6.5cm and r = 2.3 cm

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Anettt [7]

Answer:

Choice C: approximately 121 green beans will be 13 centimeters or shorter.

Step-by-step explanation:

What's the probability that a green bean from this sale is shorter than 13 centimeters?

Let the length of a green bean be X centimeters.

X follows a normal distribution with

  • mean \mu = 11.2 and
  • standard deviation \sigma = 2.1.

In other words,

X\sim \text{N}(11.2, 2.1^{2}),

and the probability in question is X \le 13.

Z-score table approach:

Find the z-score of this measurement:

\displaystyle z= \frac{x-\mu}{\sigma} = \frac{13-11.2}{2.1} = 0.857143. Closest to 0.86.

Look up the z-score in a table. Keep in mind that entries on a typical z-score table gives the probability of the left tail, which is the chance that Z will be less than or equal to the z-score in question. (In case the question is asking for the probability that Z is greater than the z-score, subtract the value from table from 1.)

P(X\le 13) = P(Z \le 0.857143) \approx 0.8051.

"Technology" Approach

Depending on the manufacturer, the steps generally include:

  • Locate the cumulative probability function (cdf) for normal distributions.
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For example, on a Texas Instruments TI-84, evaluating \text{normalcdf})(-1\text{E}99,\;13,\;11.2,\;2.1 ) gives 0.804317.

As a result,

P(X\le 13) = 0.804317.

Number of green beans that are shorter than 13 centimeters:

Assume that the length of green beans for sale are independent of each other. The probability that each green bean is shorter than 13 centimeters is constant. As a result, the number of green beans out of 150 that are shorter than 13 centimeters follow a binomial distribution.

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Let Y be the number of green beans out of this 150 that are shorter than 13 centimeters. Y\sim\text{B}(150,0.804317).

The expected value of a binomial random variable is the product of the number of trials and the probability of success on each trial. In other words,

E(Y) = n\cdot p = 150 \times 0.804317 = 120.648\approx 121

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