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Anastasy [175]
2 years ago
13

Tuition for one year at the state university Nick would like to attend is about $18,000. Nick plans to save money each month for

the next 4 years to help pay for his first year. If his parents plan to contribute $12,000 toward his first year, what is the minimum about Nick must save each month to have enough money to pay for his first year of tuition? A) $50 B) $75 C) $125 D) $250
Mathematics
2 answers:
klemol [59]2 years ago
6 0

Answer:

The answer isn't D, it's C. I don't know why a verified answer is wrong, and I don't know how people are saying it's correct. I almost failed my test because of the "verified" answer above.

Step-by-step explanation:

1. Subtract 12,000 from 18,000 (6,000).

2. Since there are 12 months in each year and he's saving money each month for 4 years, multiply 12 and 4 (48).

3.  Divide 6,000 by 48 (125).

Therefore, the answer is C. 125.

Lady bird [3.3K]2 years ago
5 0

18,000-12,000=6,000

12 months x 4 = 48

6,000 / 48= $125


so the answer is D

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Answer: hello your question is incomplete attached below is the missing codes

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Step-by-step explanation:

It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement  should be moved to the Main

<u><em>The correction  is below </em></u>

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3 years ago
What is the following quotient?
seropon [69]

Answer:  Choice B) \frac{5\sqrt{11}+5\sqrt{3}}{8}\\\\

==========================================

Work Shown:

\frac{5}{\sqrt{11}-\sqrt{3}}\\\\\\\frac{5(\sqrt{11}+\sqrt{3})}{(\sqrt{11}-\sqrt{3})(\sqrt{11}+\sqrt{3})}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{(\sqrt{11})^2-(\sqrt{3})^2}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{11-3}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{8}\\\\\\

This shows why choice B is the answer.

---------------

Explanation:

  • In the second step, I multiplied top and bottom by (\sqrt{11}+\sqrt{3})
  • This is so we can apply the difference of squares rule in step 3. The difference of squares rule is (x-y)(x+y) = x^2-y^2.
  • In step 4, the square roots cancel out with the squaring operation. The two operations are inverses of one another, which is why they cancel.

So in general, if the denominator is \sqrt{a}-\sqrt{b} and you want to rationalize the denominator, then you should multiply top and bottom by \sqrt{a}+\sqrt{b}. The same applies in reverse as well.

This leads to the denominator becoming (\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}) = (\sqrt{a})^2-(\sqrt{b})^2 = a-b

Keep in mind that a \ge 0 and b \ge 0

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lora16 [44]

Answer:

See below.

Step-by-step explanation:

So, we know that Noah's purchase can be modeled by the equation:

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The solution to the equation will be the value of x.

In this case, x will represent the original price of the jeans.

We know that Noah has a coupon for 10% off the <em>original price of the jeans</em>.

So, 0.1x will represent how much of the original price Noah gets a a discount on.

Therefore, (x - 0.1x) represents the total cost of the jeans <em>after</em> the coupon.

So, x is our original price of the jeans.

Part 2)

To verify that 70 is <em>not</em> a solution, we can simply substitute 70 for x and check whether or not the equation is true. So:

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Subtract:

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Add:

65.7\neq56.7

However, we <em>can</em> verify that 60 <em>is</em> the solution by substituting. So, substitute 60 for every x:

(60)-0.1(60)+2.7\stackrel{?}{=}5.7

Multiply:

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Subtract:

54+2.7\stackrel{?}{=}56.7

Add:

56.7\stackrel{\checkmark}{=}56.7

So, 60 is indeed the solution and is the value of x.

So, this means that $60 was the original price of the jeans.

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