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horrorfan [7]
3 years ago
9

Solve for x.

Mathematics
2 answers:
Nonamiya [84]3 years ago
7 0

-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\text{use distributive property}\\\\-\dfrac{2}{\not3_1}\cdot\not3^1x+\dfrac{8}{3}+3x=\dfrac{5}{6}\\\\-2x+3x+\dfrac{8}{3}=\dfrac{5}{6}\ \ \ \ |-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8\cdot2}{3\cdot2}\\\\x=\dfrac{5}{6}-\dfrac{16}{6}\\\\\boxed{x=-\dfrac{11}{6}}

Other method:

-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\cdot6\\\\2(-2)(3x-4)+18x=5\\\\-4(3x-4)+18x=5\ \ \ \ |\text{use distributive property}\\\\-12x+16+18x=5\ \ \ \ |-16\\\\6x=-11\ \ \ \ |:6\\\\\boxed{x=-\dfrac{11}{6}}

Vikentia [17]3 years ago
5 0

Answer:

x=  -11/6

Step-by-step explanation:

I took the test!

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The cost plus meal would be $8.55 
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Please help with multiple choice question
Volgvan

Answer:

D:   {9, 21, 33}

Step-by-step explanation:

Ken worked 2, 8 and 14 hours on 3 separate days.

For working 2 hours, his earnings were f(2) = 2(2) + 5, or 9;

For working 8 hours, his earnings were f(28) = 2(8) + 5, or 21; and

For working 14 hours, his earnings were f(14) = 2(14) + 5, or 33

Thus, the range of this function for the days given is {9, 21, 33} (Answer D)

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2 years ago
How can you rewrite the expression (8-5i)^2 in the form of a +bi
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2 years ago
in an examination ,80%examines passed in English ,70%in mathematics and 60% in both subject if 45 examines failed in both find t
stiv31 [10]

Answer:

135 and 135

Step-by-step explanation:

The computation is shown below:

The number of examiners who passed in only one subject is as follows

=  n(E) - n(E ∩M) + n(M) - n(E ∩M)

= (80 - 60 + 70 - 60)%

= 30%

Now the number of students who passed in minimum one subject is

n(E∪M) = n(E) + n(M) -  n(E ∩M)

= 80 - + 70 - 60

= 90%

Now the number of students who failed in both subjects is

= 100 - 90%

= 10% of total students

= 45

So total number of students appeared for this 450

So, those who passed only one subject is

= 450 × 30%

= 135

Now the Number of students who failed in mathematics is

= 100% - Passed in Mathematics

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4 0
2 years ago
Write a x (-a)x 13 x a x (-a) x 13 in power notation
miss Akunina [59]

Answer:

a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

Step-by-step explanation:

The given expression

a\times (-a)\times 13\times a\times (-a)\times 13

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

a\times (-a)\times 13\times a\times (-a)\times 13

= [13\times13][(a\times (-a)\times a\times (-a)]

As

13\times13 = 13^{2} , a\times a = a^{2} , (-a)\times (-a) = (-a)^{2}

So,

=[13^{2}][a^2\times (-a)^2]

As

(-a)^2 = a^{2}

So,

=[13^{2}][a^2\times a^2]

As ∵a^{m} \times a^{n}=a^{m+n}

=[13^{2}][a^{2+2}]

As ∵a^{m} \times a^{n}=a^{m+n}

=13^{2}\times a^{4}

=a^{4}\times 13^{2}

Therefore, a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

<em>Keywords: power notation</em>

<em>Learn more about power notation from brainly.com/question/2147364</em>

<em>#learnwithBrainly</em>

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