Answer:
D: {9, 21, 33}
Step-by-step explanation:
Ken worked 2, 8 and 14 hours on 3 separate days.
For working 2 hours, his earnings were f(2) = 2(2) + 5, or 9;
For working 8 hours, his earnings were f(28) = 2(8) + 5, or 21; and
For working 14 hours, his earnings were f(14) = 2(14) + 5, or 33
Thus, the range of this function for the days given is {9, 21, 33} (Answer D)
Answer:
135 and 135
Step-by-step explanation:
The computation is shown below:
The number of examiners who passed in only one subject is as follows
= n(E) - n(E ∩M) + n(M) - n(E ∩M)
= (80 - 60 + 70 - 60)%
= 30%
Now the number of students who passed in minimum one subject is
n(E∪M) = n(E) + n(M) - n(E ∩M)
= 80 - + 70 - 60
= 90%
Now the number of students who failed in both subjects is
= 100 - 90%
= 10% of total students
= 45
So total number of students appeared for this 450
So, those who passed only one subject is
= 450 × 30%
= 135
Now the Number of students who failed in mathematics is
= 100% - Passed in Mathematics
= 100% - 70%
= 30% of 450
= 135
Answer:
can be written in power notation as 
Step-by-step explanation:
The given expression

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:
Let

= ![[13\times13][(a\times (-a)\times a\times (-a)]](https://tex.z-dn.net/?f=%5B13%5Ctimes13%5D%5B%28a%5Ctimes%20%28-a%29%5Ctimes%20a%5Ctimes%20%28-a%29%5D)
As
,
,
So,
![=[13^{2}][a^2\times (-a)^2]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E2%5Ctimes%20%28-a%29%5E2%5D)
As

So,
![=[13^{2}][a^2\times a^2]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E2%5Ctimes%20a%5E2%5D)
As ∵
![=[13^{2}][a^{2+2}]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E%7B2%2B2%7D%5D)
As ∵


Therefore,
can be written in power notation as 
<em>Keywords: power notation</em>
<em>Learn more about power notation from brainly.com/question/2147364</em>
<em>#learnwithBrainly</em>