All categories

3 years ago

1/3 +5 =how do I solve

Mathematics

2 answers:

jarptica [38.1K]3 years ago

4 0

Answer: 16/3 or 5.333333

Step-by-step explanation:

1/3 is 0.3333333 so 0.3333333 + 5 is 5.333333

Alinara [238K]3 years ago

3 0

Answer:

1/3 + 5 = 16/3 or 5 1/3

Step-by-step explanation:

First we convert 5 to a equal fraction towards 1/3.

5 = 5/1 = 15/3

Then we add 15/3 and 1/3.

15/3 + 1/3 = 16/3.

16/3 = 5 1/3.

So, the answer is 16/3 or 5 1/3.

Hope this helps! :)

You might be interested in

g An urn contains 10 balls: 4 red and 6 blue. A second urn contains 16 red balls and an unknown number of blue balls. A single b

Fed [463]

Answer:

Therefore the of blue in the second urn is 4.

Step-by-step explanation:

Let second urn contain x number of blue ball .

Urn Red Ball Blue Ball Total Ball

1 4 6 10

2 16 x 16+x

Getting a red ball from first urn is $P(R_1)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{4}{10}$

Getting a blue ball from first urn is $P(B_1)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {6}{10}$

Getting a red ball from second urn is $P(R_2)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{16}{16+x}$

Getting a blue ball from second urn is $P(B_2)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {x}{16+x}$

Getting two red balls from first and second urn is $=\frac{4}{10}\times \frac{16}{16+x}$

$=\frac{32}{5(16+x)}$

Getting two blue balls from first and second urn is $=\frac{6}{10}\times \frac{x}{16+x}$

$=\frac{3x}{5(16+x)}$

The probability that both balls are the same in color is $=\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}$

Given that the probability that both balls are the same in color is 0.44.

According to the problem,

$\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}=0.44$

$\Rightarrow \frac{32+3x}{5(16+x)} =0.44$

$\Rightarrow \frac {32+3x}{(80+5x)} =0.44$

$\Rightarrow 32+3x =0.44(80+5x)$

$\Rightarrow 32+3x =35.2 +2.2x$

$\Rightarrow 3x -2.2 x= 35.2 -32$

$\Rightarrow 0.8x= 3.2$

$\Rightarrow x = 4$

Therefore the of blue in the second urn is 4.

5 0

3 years ago

HELP

kherson [118]

Answer: For the equation simply substitute 30 in for v and 4 in for s in the equation given, so H=-16t^2+30t+4

Part 2.

If the juggler misses the ball, you wish to know the time that it takes for the ball to travel the four feet from his hand to the ground, so respectively,

4=-16t^2+30t+4 or 0=-16t^2+30t or 0 = -16t+30,

solving for t, t =30/16 seconds or 1.875 seconds

Step-by-step explanation:

4 0

3 years ago

Please help me with this problem <br> Evaluate (-½·3)³

-Dominant- [34]

Answer: -27/8

Step-by-step explanation:

$\left(-\frac{1}{2}\cdot \:3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\quad \mathrm{if\:}n\mathrm{\:is\:odd}$

$\left(-\frac{1}{2}\cdot \:3\right)^3=-\left(\frac{1}{2}\cdot \:3\right)^3$

$=-\left(\frac{1}{2}\cdot \:3\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$\left(\frac{1}{2}\cdot \:3\right)^3=\left(\frac{1}{2}\right)^3\cdot \:3^3$

$=-\left(\frac{1}{2}\right)^3\cdot \:3^3$

$=-\frac{1}{8}\cdot \:3^3$

$=-\frac{1}{8}\cdot \:27$

$=-\frac{27}{8}$

3 0

2 years ago

An initial population of 535 quail increases at an annual rate of 25%. Write an exponential function to model the quail populati

olchik [2.2K]

Answer: c

Step-by-step explanation:

5 0

3 years ago

Please Simplify 5(x - 6)

nordsb [41]

Our equation looks like:

$5(x-6)$

This means that we will need to distribute. This means that we need to multiply everything inside the parenthesis by the number outside of the parenthesis. (<em>Note: you only distribute when variables are involved.)</em>

$(5 \cdot x)-(5 \cdot 6)$

Simplify:

$5x-30$

We cannot simplify any further, so we know that our equation, until we know what x equals, is $5x - 30$ .

4 0

3 years ago

Read 2 more answers

1/3 +5 =how do I solve ​

1/3 +5 =how do I solve